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3 years ago

Ten subtracted from a number if the difference is 30 what was the orginal number

Mathematics

1 answer:

nadezda [96]3 years ago

5 0

X-10=30

X=30+10

X= 40

So the original number was 40 and you can prove it by subtracting 10 so 40-10= 30

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3 years ago

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B is the midpoint

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3 years ago

Find the consecutive positive odd integers whose product is 99

dezoksy [38]

Answer:

9 and 11

Step-by-step explanation:

So let's say that the first integer is x.

That means that the second integer is x+2, since it us the next odd number.

This problem can be easily solved with our mind the answer is 9 and 11, but I'll show you the steps to slove this.

We make an equation using these two numbers:

$(x)*(x+2)=99\\$

Now all we gotta do is solve for x:

$x^2 +2x = 99\\x^2+2x-99=0$

Now we use either splitting the middle term or quadratic formula:

$x^2+11x-9x+99=0\\x(x+11)-9(x+11)=0\\(x+11)(x-9)=0$

Now we split each terma and solve for x:

$(x-9)=0\\x=9\\(x+11)=0\\x=-11$

Now the question states <em>positive </em>so we can rule out x = -11.

Now we have the first integer x = 9,

the second integer is x+2 = 9+2 =11

So the two consecutive positive odd integers are 9 and 11

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3 years ago

Ten subtracted from a number if the difference is 30 what was the orginal number​

Ten subtracted from a number if the difference is 30 what was the orginal number