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solong [7]
4 years ago
9

Which of the following is a solution for the equation y=4x+5

Mathematics
1 answer:
Ronch [10]4 years ago
6 0

Answer:

X = - 5/3 or X = -1.6

Step-by-step explanation:

Move variable to the left hand side and change its sign

Collect like terms

Divide both sides of the equation by -3

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Using each of the digits 1 to 9 once and only once form two whole numbers one of which is double the other
Vadim26 [7]
Answer
9,327 and 18,654
6 0
3 years ago
Find the Least Common Multiple (LCM) of 50 and 90​
Effectus [21]

Answer:

450

(I can't post the answer if it's less than 20 letters so just ignore this I'm trying to fill up)

7 0
3 years ago
The length of a rectangle is 7 cm than 6 times its width. It's area is 10 square centimeters. Find the dimensions
ad-work [718]
So legnth is 7 more than 6 times width
l=7+6w
area=10 cm^2

lw=area

subsitute
7+6w for l
(7+6w)(w)=10
7w+6w^2=10
subtract 10 from both sides
6w^2+7w-10=0
factor
multiply 6 and -10
get -60
now find what 2 numbers multiply to get -60 and add to get 7
the answe ris -5 and 12
split up 7w into that
6w^2+7w-10=0
6w^2+12w-5w-10=0
group
(6w^2+12w)+(-5w-10)=0
undistribute factors
(6w)(w+2)+(-5)(w+2)=0
reverse distribute (ab+ac=a(b+c)
(w+2)((6w)+(-5))=0
(w+2)(6w-5)=0
set each to zero
w+2=0
subtract 2
w=-2
false, legnths cannot be negative

6w-5=0
add 5
6w=5
divide both sides by 6
w=5/6
subsitute
l=7+6w
l=7+6(5/6)
l=7+5
l=12


legnth=12 cm
width=5/6 cm

7 0
4 years ago
Determine the number of cement blocks needed to put up a wall measuring 20 meters in length and 1.5 meters in height. Each block
Montano1993 [528]

calculate area of wall

20 x 1.5 = 30 square meters

 now calculate area of 1 block

12 x 18 =216 square centimeters

 convert cm to meters  1 cm^2 = 0.0001m^2

 so 216 x 0.0001 = 0.0216 sq meter for 1 block

 divide area of wall by area of block

30/0.0216 = 1388.88 so 1389 blocks are required.

8 0
3 years ago
Simplify the following expression please solve correctly<br> −12^12 ^2 / 3^ 5 ^5
nikdorinn [45]

The simplified expression is -\frac{48}{x^{3} y^{3}}

Explanation:

The given expression is \frac{-12x^{2}12y^{2}  }{3x^{5} y^{5} }

Let us simplify the expression.

Multiplying the numbers in the numerator, we have,

\frac{-144 x^{2} y^{2}}{3 x^{5} y^{5}}

Dividing the term 144 by 3, which results in 48.

Thus, we have,

\frac{-48 x^{2} y^{2}}{x^{5} y^{5}}

Applying the fraction rule \frac{-a}{b}=-\frac{a}{b} , we get,

-\frac{48 x^{2} y^{2}}{x^{5} y^{5}}

Applying the exponent rule \frac{x^{a}}{x^{b}}=\frac{1}{x^{b-a}}, we have,

-\frac{48}{x^{3} y^{3}}

Thus, the simplified expression is -\frac{48}{x^{3} y^{3}}

7 0
3 years ago
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