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Elodia [21]
3 years ago
11

118 {121÷(11×11)-(-4)-(3-7)}​

Mathematics
2 answers:
Rama09 [41]3 years ago
5 0

<u>Q</u><u>uest</u><u>ion</u><u>:</u>

To Simplify:

118 {121÷(11×11)-(-4)-(3-7)}

<u>Solu</u><u>tion</u>:

↠118 {121÷121+4-(-4)}

↠118 {1+4+4}

↠118 {5+4}

↠118{9}

↠118×9

↠1062

▬▬▬▬▬▬▬▬▬▬▬▬

The upper Solution is done by applying BODMAS

<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>

B→ Bracket

O→ Of

D→ Division

M→ Multiplication

A→ Addition

S→ Subtraction

cricket20 [7]3 years ago
5 0

Answer:

1062

Step-by-step explanation:

First do what’s in the parentheses, then start solving it by doing what’s on the far left that still is in the brackets after solving everything in the bracket multiply it by 118

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4 0
3 years ago
Your ship sinks and you swim to a nearby island. On this island, the inhabitants do not use money. The island residents use isla
natita [175]

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Step-by-step explanation:

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Read 2 more answers
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velikii [3]

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7 0
2 years ago
Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)
Maurinko [17]

Answer:

Therefore the required Equation of Circle

x^{2}+y^{2}-2x+12y+12=0

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0

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Applying Distributive Property we get

x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0

Therefore the required Equation of Circle

x^{2}+y^{2}-2x+12y+12=0

6 0
3 years ago
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