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Nataly_w [17]
3 years ago
5

Graph the function and answer each of the following questions. f(x)=-3x+5 What is the y-intercept? What is the slope (in fractio

n form)? Is your slope positive or negative? Explain how you plotted your second point.

Mathematics
2 answers:
blondinia [14]3 years ago
8 0

Answer:

The slope is -3 and the y intercept is 5

The y intercept is 5

The slope in fraction form is -3/1  

The slope is negative

Step-by-step explanation:

f(x) = -3x+5

This is written in the form  y=mx+b  where m is the slope and b is the y intercept

The slope is -3 and the y intercept is 5

The y intercept is 5

The slope in fraction form is -3/1  

The slope is negative

The first point plotted is the y intercept (0,5)  The y intercept is where x =0

The second point is from the slope.  The slope is the change in y over the change in x.    We go down 3 ( since the 3 is negative) and to the right 1 (since it is positive) (1,2)

iris [78.8K]3 years ago
7 0

Answer:


Step-by-step explanation:

Answer:

(i)

y-intercept is 5

(ii)

slope is \frac{-3}{1}

(iii)

slope is negative

(iv)

another point is (3,-4)

Step-by-step explanation:

We are given equation as

f(x)=-3x+5

now, we can compare it with slope intercept form of line

y=mx+b

where

m is slope

b is y-intercept

we get

m=\frac{-3}{1}

b=5

So,

(i)

y-intercept is 5

(ii)

slope is \frac{-3}{1}

(iii)

we can see that

m=\frac{-3}{1}

is a fraction and negative

so, slope is negative

(iv)

we can select any random value of x and find y

that will give us second point

Let's assume

x=3

y=\frac{-3}{1}\times 3+5

y=-9+5

y=-4

So, another point is (3,-4)

(v)

Graph:


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6 0
3 years ago
HELP! Please pyth. theorem
Alex

<u>Given</u>:

The given triangle QPO is a right triangle.

The length of QP is 5 units.

The length of OP is (x + 5) units.

The length of QO is (x + 6) units.

We need to determine the hypotenuse of the triangle QPO.

<u>Value of x:</u>

The value of x can be determined using the Pythagorean theorem.

Thus, we have;

QO^2=QP^2+OP^2

Substituting the values, we get;

(x+6)^2=5^2+(x+5)^2

Expanding, we get;

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Adding the like terms, we get;

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Thus, the value of x is 7.

<u>Length of the hypotenuse:</u>

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4 0
3 years ago
Find each. a. za_2 for the 99% confidence interval b. za_2 for the 98% confidence interval c. za_2 for the 95% confidence interv
irga5000 [103]

Answer:

a) Z = 2.575.

b) Z = 2.327.

c) Z = 1.96.

d) Z = 1.645.

e) Z = 1.88.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Question b:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Question c:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Question d:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Question e:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.94}{2} = 0.03

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.03 = 0.97, so Z = 1.88.

8 0
3 years ago
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