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irina1246 [14]
2 years ago
7

I need help finding Sin B, Cos B, and Tan A for a geometry problem. please help meee

Mathematics
1 answer:
Scilla [17]2 years ago
6 0

Answer:

Sin B = 5/13

Cos B = 12/13

tan A = 12/5

Step-by-step explanation:

Sin B = opposite side/ hypotenuse

Sin B = 5/13

Cos B = adjacent side / hypotenuse

         = 12/13

tan A = opposite side /adjacent side

          = 12/5

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2 years ago
A fish tank has the shape of a rectangular prism. It has a length of 214 meters, width of 78 meters, and a height of 112 meters.
lesya692 [45]

Answer:

2 61/64 m2

Step-by-step explanation:

V = length * width * height

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5 0
3 years ago
Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

                              P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0

Thus,

                                    Q_x -P_y = 0 -2 = - 2

Now, by the Green's theorem, we have

\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x  \Big|_{-3}^{4} = -42

4 0
3 years ago
Find the value of each trigonometric ratio
oee [108]

:) Hope this answers your question :)

3 0
3 years ago
The table represents a linear function. Which is the slope of the function?
Galina-37 [17]

From the table we have the points (-4, -2) and (-2, -10).

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

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<h3>Answer: The slope = -4.</h3>
7 0
3 years ago
Read 2 more answers
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