Forwarded events can only be recorded when systems ADMINISTRATORS have de-established an event subscription. TRUE or FALSE

Project management software helps you develop a ______________, which serves as a basis for creating Gantt charts, assigning res

meriva

Answer:

Work breakdown structure.

Explanation:

The Work breakdown structure is used in project management which divided the project into smaller parts in software development. When the project is divided into the smaller parts it is distributed that part individually in the member of the project.

The main advantage of Work breakdown structure when it is divided into smaller parts it is easy to maintain and project work in a very efficient manner also the development of the project in a very fast manner.

4 0

3 years ago

C++ Code Outputs.

mojhsa [17]

Answer:

#include

using namespace std;

struct courseInfo{

string name;

int unit;

char grade;

};

struct Student {

string fName;

string lName;

string idNumber;

courseInfo courses[2];

int unitCompleted;

double gpa;

};

Student s;

bool openFile(ifstream &in);

void Print_info_one(Student s);

void Read_info(Student &s);

float Find_points(char c) ;

bool openFile(ifstream &inFile){

string line;

int i=0,k=0;

string fName="", lname="", id="", name1="", name2="";

char grade1, grade2;

int unit1, unit2;

if (inFile.is_open())

{

while (getline(inFile, line))

{

while (line[i] != ',')

{

fName += line[i];

i++;

}

i++;

while (line[i] != ' ')

{

lname += line[i];

i++;

}

i++;i++;

while (line[i] != ' ')

{

id += line[i];

i++;

}

i++;

int count=0;

while (count <2)

{

name1 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade1 = line[i];

i++;i++;

unit1 = line[i]-'0';

i++;i++;

count=0;

while (count <2)

{

name2 += line[i];

i++;

if(line[i] == ' ' ) count++;

}

i++;

grade2 = line[i];

i++;i++;

unit2 = line[i]-'0';

}

inFile.close();

s.fName = fName;

s.lName = lname;

s.idNumber = id;

s.courses[0].name = name1;

s.courses[0].grade = grade1;

s.courses[0].unit = unit1;

s.courses[1].name = name2;

s.courses[1].grade = grade2;

s.courses[1].unit = unit2;

s.unitCompleted = unit1 + unit2;

s.gpa = (unit1*Find_points(grade1) + unit2*Find_points(grade2))/(unit1+unit2);

}

else

{

cout << "Error reading file\n";

return false;

}

return true;

}

void Print_info_one(Student s){

cout << "Name: " << s.fName << ", " << s.lName << " ID Number: " << s.idNumber << " Course 1 Name: " << s.courses[0].name << " Grade: "

<< s.courses[0].grade << " Units: " << s.courses[0].unit << " Course 2 Name: " << s.courses[1].name << " Grade: "

<< s.courses[1].grade << " Units: " << s.courses[1].unit << " Unit completed: " << s.unitCompleted << " GPA:" << s.gpa << endl;

}

void Read_info(Student &s){

}

float Find_points(char grade){

switch (grade)

{

case 'A':

return 4.0;

break;

case 'B':

return 3.0;

break;

case 'C':

return 2.0;

break;

case 'D':

return 1.0;

break;

case 'F':

return 0;

break;

default:

break;

}

return 0;

}

int main() {

ifstream inFile;

std::fstream fs;

fs.open ("input.txt", std::fstream::in );

Print_info_one(s);

return 0;

Explanation:

5 0

3 years ago

For each of the descriptions below, perform the following tasks:

zlopas [31]

Answer:

Explanation:

The underlined traits in the ER chart speak to essential key since they remarkably recognize the quality

(a)

(I) The level of the given relationship is 2 i.e it is a parallel connection among Book and Publisher. It is a one to numerous relationship from distributer to book in light of the fact that a distributer can distribute any number of books however a book will have only one publisher,so the cardinality will be 1 to 1..* (one to many)

(b)

(i) The degree of the given relationship is 2 i.e it is a binary relationship between Author and Book. It is a many to many relationship from Book to Author a book can be written by one or more authors and an author can write more than one book, so the cardinality will be 1..* to 1..* (many to many)

(c)

(i) As mentioned in part (b), the degree of given relation is 2 and cardinality is many to many (1..* to 1..*)

(d)

(i) The degree of the given relationship is 1 i.e unary relationship. It is a many to many relationship because one book can belong to any sets and a set can have any number of books, so cardinality is 1..* to 1..* (many to many)

Note: attached below is the image of various options to confirm the explanation (answer).

cheers i hope this helped !!!

4 0

4 years ago

DRU is a small brokerage house that enables its clients to buy and sell

Rudik [331]

The complete question rather reads;

DRU is a small brokerage house that enables its clients to buy and sell

stocks over the Internet, as well as place traditional orders by phone or Fax. DRU has just decided to install a new e-mail package. One vendor offering an SMTP-based two-tier client-server architecture. The second vendor is offering a Web-based e-mail architecture. DRU doesn't understand either one but thanks the Web-based one should be better because, in their words, "the Web is the future".

(a) Briefly explain to DRU management, in layperson's terms, the difference between the two.

(b) Outline the pros and cons of the two alternatives and

(c) Recommend to DRU about which is better

Explanation:

a) SMTP stands for Simple Mail Transfer Protocol. Thus, put simply an SMTP-based two-tier client-server architecture is a package that involves using a client-server provider like Outlook. This implies that Outlook provides the client with his own unique PO Box (server) so to speak.

While the Web-based e-mail architecture enables the DRU access to online mail platforms like G-mail with little server customisation features.

b. The Web-based e-mail architecture is good for personal email activities because of its ease of operation, however, it does not provide top security and customisation features. While an SMTP-based two-tier client-server architecture allows for unique server customisation with added security features as well be suitable for larger organisational work. Although a disadvantage is that it may cost more and quite a complex process to learn.

c) Since DRU is a growing firm the SMTP-based two-tier client-server architecture would be recommended as this would provide it will efficient customer service delivery.

6 0

3 years ago

Alex, a web designer, is assigned the task of creating a mobile device-friendly website for a leading fashion outlet called AllS

Katyanochek1 [597]

Answer: Pulldown menus

Explanation:

Pulldown menus refer to the graphical control element, that is identical to a list box, which enables user to be bake to select one value from a list.

They're regarded as the menu of options that will appear when an item is selected with a mouse. In this case, the item that the user selected will show at the top of the display screen, while the menu appears will show below it.

Therefore, Alex should use the pulldown menus to hide the long list of hypertext links so that it appears only in response to a tap of a major heading in the navigation list.

6 0

3 years ago