Given:
Equation of line
.
To find:
The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.
Solution:
The given equation of line can be written as

Slope of line is



Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is


![[\because m_1=\dfrac{7}{4}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20m_1%3D%5Cdfrac%7B7%7D%7B4%7D%5D)
Now, the slope of perpendicular line is
and it goes through (-21,2). So, the equation of line is






Therefore, the required equation in slope intercept form is
.
A = P( 1 + rt)
A/P = 1 + rt
A/P - 1 = rt
t = (( A/P)) - 1)/r
t = (( 5500/1000) - 1)/(6.25/100
t = (5.5 - 1)/0.0625
t = 4.5/0.0625 = 72 years
Answer it will take 72 Years...
Hope it helps!!!!!
Make the equations equal and solve for x
- 2x²+6x+1=-4x²+1
- 6x²+6x=0
- 6x(x+1)=0
- 6x=0 or x+1=0
- x=0 or x=-1
For x=0
For x=-1
The solutions are
Graph attached
Answer:
Step-by-step explanation:
= (x^2 + h^2 - 2xh) + (y^2 + k^2 - 2yk) As, (a-b)^2 = a^2 + b^2 - 2ab
= x^2 + h^2 - 2xh + y^2 + k^2 - 2yk