Determine which value is equivalent to | f ( i ) | if the function is: f ( x ) = 1 - x. We know that for the complex number: z = a + b i , the absolute value is: | z | = sqrt( a^2 + b^2 ). In this case: | f ( i )| = | 1 - i |. So: a = 1, b = - 1. | f ( i ) | = sqrt ( 1^2 + ( - 1 )^2) = sqrt ( 1 + 1 ) = sqrt ( 2 ). ANSWER IS C. sqrt( 2 )
Answer:
Step-by-step explanation:
A 2nd order polynomial such as this one will have 2 roots; a 3rd order polynomial 3 roots, and so on.
The quadratic formula is one of the faster ways (in this situation, at least) in which to find the roots. From 2x^2 + 4x + 7 we get a = 2, b = 4 and c = 7.
Then the discriminant is b^2 - 4ac, or, here, 4^2 - 4(2)(7), or -40. Because the discriminant is negative, we know that the roots will be complex and unequal.
Using the quadratic formula:
-4 ±√[-40] -4 ± 2i√10
x = ------------------ = ------------------
4 4
-2 ± i√10
Thus, the roots are x = ------------------
2
B.) a=-5.7
1.6(a)=-9.12
(a)=(-9.12)/(1.6)
a=-5.7
Answer:
I need more information to answer this. Please provide more context
Step-by-step explanation:
SOHCAHTOA
SIN: Opposite/hypo
COS: Adj/Hyp
TAN: Opp/Adj
