Can you help me with my math

Roman is considering buying shares of GHI stock. The stock currently sells for $60 per share. The stock changes in value at 8:00

Fynjy0 [20]

Answer:

The Probability that the GHI is less than $70 in three days is 1% or 0.01

Step-by-step explanation:

Here, we want to find the probability that the GHI is less than $70.

So what we do here is to find the scenarios that could make the $60 less than $70 is three days;

Scenario 1;

Two days decrease and one day increase

That will bring the value to 60 -1-1 + 10 = $68 which is less than 70

Scenario 2;

Three days decrease

That will bring the value to

60-1-1-1 = 57 which is less than 70

Any other possible scenario to make the value of the share less than 70? NO !

For the 1st case scenario;

Two days decrease and one day increase;

The scheduled probabilities will be as follows;

Kindly recall, probability of increase = 90% = 90/100 = 0.9

Probability of decrease = 10% = 10/100 = 0.1

So probability in scenario 1 will be;

P(Two days decrease and one day increase)

= 0.1 * 0.1 * 0.9 = 0.009

Kindly note this can happen in any order and since no order was specified, we do not need to consider other cases

Scenario ii

Three days decrease

That will be;

P(three days decrease) = 0.1 * 0.1 * 0.1 = 0.001

So the addition of both since we will be having either of the two and or means addition in probability will be ;

0.001 + 0.009 = 0.01 = 1%

4 0

2 years ago

∫ (1-sin²3t)cos3t du

Schach [20]

Substitute $y=\sin3t$ , so that $\mathrm dy=3\cos3t\,\mathrm dt$ (not $\mathrm du$ !). Then

$\displaystyle\int(1-\sin^23t)\cos3t\,\mathrm dt=\frac13\int(1-y^2)\,\mathrm dy=\frac y3-\frac{y^3}9+C=\frac{\sin3t}3-\frac{\sin^3t}9+C$

3 0

3 years ago

I got every other question but this one. please help

bogdanovich [222]

$\csc( \alpha ) = \frac{1}{ \sin( \alpha ) } \\$
------------------
$\sin( \alpha ) = \frac{11}{5 \sqrt{5} } = \frac{11 \sqrt{5} }{25}$

5 0

2 years ago

A surveillance camera is located on a lamp post above a parking lot. The equation of the viewing area on an overhead grid is (x

mezya [45]

The given equation is the equation of the circle, as the coefficients of x² and y² have same values and same signs. This means the camera is located at the center of the circle.

The equation is in standard form, we can directly find the center of the circle to be (9, -3) and the radius of the circle is 7.

The car is parked at the location (-2, 5). Using the distance formula we can find the distance from camera to the car.

Using the distance formula we can write:

$\sqrt{(9+2)^{2} + (-3-5)^{2} } \\ \\ 
= \sqrt{121+64} \\ \\ 
= \sqrt{185} \\ \\ 
=13.6$

Thus the car is parked at a distance of 13.6 units from the location of the camera.

7 0

3 years ago

7. Two classes have car washes to raise money for class trips. A portion of the

postnew [5]

Based on the information given, the percentage for the trip earnings rate for class A and B is 80% and 70% respectively.

<h3>How to calculate percentage.</h3>

From the information given, the trip earnings rate for A will be calculated thus:

= 16/20 × 100.

= 80%

The trip earnings rate for B will be calculated thus:

= 14/20 × 100

= 70%

Learn more about percentages on:

brainly.com/question/24304697

8 0

2 years ago