The pattern is adding 2 stars on top of the previous figure, so figure number 4 would look like this:
* *
* *
* *
* *
Since the pattern is adding 2 stars every time, the explicit formula (for the number of stars) would be
Since when n=1, i.e. figure 1, we have 2*1=2 stars
when n=2, i.e. figure 2, we have 2*2=4 stars
when n=3, i.e. figure 3, we have 2*3=6 stars
and so on.
The recursive formula lays on the fact that we add 2 stars to the previous figure, which means that the fomula is
In fact, what we just wrote is simply "the number of stars at a given iteration is the number of stars at the previous iteration, plus 2.
Find delta y/delta x
(10-7)/(15-12)=3/3=1, (15-10)/(20-15)=5/5=1
y=x+b, using any point, I'll use (20,15) we can solve for b...
15=20+b
b=-5 so our line is:
y=x-5, and we want to know when y=17
17=x-5
x=22
so n=22
In order from least to greatest: 25%, 3/5, 2/3
Answer:
<h2>See the explanation.</h2>
Step-by-step explanation:
Sin2α = 2SinαCosα.
Cos2α = (Cosα)^2 - (Sinα)^2.
Sin4α can be written as Sin2(2α).
Similarly Cos4α can be written as Cos2(2α).
It is given that tanα=3.
Sinα(Sinα) = [], the values either be both positive or both negative, as the value of tanα is positive only on first and third quadrant.
Sin4α = .
Cos4α =
Answer:
45+5x
Step-by-step explanation:
45 for initial
5 for every hour
x is amount of hours