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Luda [366]
3 years ago
5

GEOMETRY HELP PLEASE!!! FAST!!!

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

The <em><u>correct answer</u></em> is:

Rotation of 90° counterclockwise about the origin  and a translation 2 units right

Explanation:

A rotation 90° counterclockwise maps each point (x, y) to (-y, x).  This means our points would be:

A(-4,3)→(-3, 4); B(-1,3)→(-3, -1); C(-2,1)→(-1, -2)

A translation 2 units right will add 2 units to the new x-coordinates; this gives us

(-3, 4)→(-1, 4); (-3, -1)→(-1, -1); and (-1, -2)→(1, -2)

These are the points in the image, so this is the correct set of transformations.

You might be interested in
Sam found $1.8 After finding the money in his pocket, Sekou finds an additional $0.75 in his backpack. Then he decides to buy a
Kitty [74]

Answer:

Hey there!

Sam's Money=1.80 dollars + 0.75 dollars.

1.80+0.75-1.50=1.05

1.05/0.13= 8.08.

He will be able to buy 8 pieces of gum.

Let me know if this helps :)

7 0
3 years ago
2. The food pantry of Ellicottville received a huge donation of fruit snacks during the month of December. The table below shows
mestny [16]

ANSWER

238\text{ fruit snacks per after-school program}

EXPLANATION

We have that there are 12 after school programmes and each one got an equal number of packages.

To find the number of fruit snacks that each received, we have to find the total number of fruit snacks.

The total number of fruit snacks can be found by multiplying the number of boxes of each flavor by the number of packages in each box, then adding them up:

\begin{gathered} \text{TOTAL}=(48\cdot4)+(78\cdot9)+(90\cdot11)+(108\cdot9) \\ \text{TOTAL}=192+702+990+972 \\ \text{TOTAL}=2856\text{ fruit snacks} \end{gathered}

Now, to <em>find the number of fruit snacks that each received</em>, divide by 12:

\begin{gathered} \frac{2856}{12} \\ 238\text{ fruit snacks per after-school program} \end{gathered}

8 0
1 year ago
In a sample of 700 gas​ stations, the mean price for regular gasoline at the pump was $2.894 per gallon and the standard deviati
frez [133]

Answer:

P(x < 2.892) = 4.36\%

Step-by-step explanation:

Given

N = 700 --- Population

\mu = 2.894 -- Mean

\sigma = 0.009 --- Standard deviation

n = 55 -- Sample

Required: P(x < 2.892)

This question will be solved using the finite correction factor

First, calculated the z score

z = \frac{x - \mu}{\sqrt{\frac{N -n}{N -1}} * \frac{\sigma}{\sqrt n}}

z = \frac{2.892 - 2.894}{\sqrt{\frac{700 -55}{700 -1}} * \frac{0.009}{\sqrt {55}}}

z = \frac{-0.002}{\sqrt{\frac{645}{699}} * \frac{0.009}{7.42}}

z = \frac{-0.002}{\sqrt{0.92} * \frac{0.009}{7.42}}

z = \frac{-0.002}{0.95917 * 0.0012129}

z = -1.71

So:

P(x < 2.892) = P(z < -1.71)

Using z table

P(x < 2.892) = 0.043633

P(x < 2.892) = 4.36\%

3 0
3 years ago
What is the value of ​2×[34−5×(3+1)]​ ?
spayn [35]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{28}}}}}

Step-by-step explanation:

Use BODMAS rule :

Bracket , Of , Division , Multiplication , Addition , Subtraction

\sf{2 \times [ 34 - 5 \times (3 + 1) ] }

Add the numbers : 3 and 1

\dashrightarrow{ \sf{2 \times [ 34 - 5 \times 4 ] }}

Multiply the numbers : 5 and 4

\dashrightarrow{ \sf{2 \times [ 34  - 20 \: ]  }}

Subtract 20 from 34

\dashrightarrow{ \sf{2 \times 14}}

Multiply the numbers : 2 and 14

\dashrightarrow{ \sf{28}}

Hope I helped!

Best regards! :D

4 0
3 years ago
If z varies jointly with x and y, x = 2 and y = 2, z = 7. Find z when x = 4 and y = 8.
Wittaler [7]

Answer:

56

Step-by-step explanation:

z varies jointly with x and y:

z = kxy

When x = 2 and y = 2, z = 7.

7 = k(2)(2)

k = 7/4

z = 7/4 xy

When x = 4 and y = 8:

z = 7/4 (4)(8)

z = 56

7 0
3 years ago
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