All categories

3 years ago

Can some please explain how to do the math?

Mathematics

1 answer:

MatroZZZ [7]3 years ago

6 0

Answer:

60/5=12

The enrollment drop is 12 students per year

Step-by-step explanation:

60/5=12

=12

You might be interested in

A movie club charges a one-time fee membership fee of $25. This allows members to purchase movies for $7 each. Lincoln is a memb

AleksAgata [21]

Answer:

he purchased 5 movies bro

Step-by-step explanation:

3 0

4 years ago

Find the distance between the points (4, –2) and (0, 10).

madam [21]

$A(4,-2) \\B(0, 10) \\AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\AB=\sqrt{(0-4)^2+(10-(-2))^2} \\AB=\sqrt{16+144} \\AB=\sqrt{160}\approx\boxed{12.65} \\$

The answer is D.

Hope this helps.

r3t40

8 0

4 years ago

Steven bought treats for his friends at the mall food court. Where m,n,p, and q are whole numbers, the amount Steven spent on th

Fed [463]

We have that the term from the expression that represents the amount of money Steven spent on cinnamon rolls is

X=3.19p

From the question we are told that

m,n,p, and q are whole numbers,

Expression Total amount spent =2.35m + 2.75n + 3.19p + 3.39q

Cost of cinnamon rolls=\$3.19

Generally the equation for the Money spent on cinnamon roll is mathematically given as

X=No of cinnamon roll * Cost of cinnamon roll

X=3.19*p

X=3.19p

For more information on this visit

brainly.com/question/23366835?referrer=searchResults

7 0

3 years ago

What is the sum of the infinite geometric series? -3-3/2

Juliette [100K]

Answer:

To find the sum of an infinite geometric series having ratios with an absolute value less than one, use the formula, S=a11−r , where a1 is the first term and r is the common ratio.

6 0

3 years ago

Read 2 more answers

Find sec 2Theta in exact value

forsale [732]

Answer:

$sec(2\theta)=-\frac{5}{4}$

Step-by-step explanation:

we know that

step 1

Find $cos(\theta)$

we know that

$tan^2(\theta)+1=sec^2(\theta)$

we have

$tan(\theta)=3$

substitute

$3^2+1=sec^2(\theta)$

$sec^2(\theta)=10$

$sec(\theta)=\pm\sqrt{10}$

Remember that

Angle theta lie in Quadrant I

$sec(\theta)$ is positive

$sec(\theta)=\sqrt{10}$

Remember that

$sec(\theta)=\frac{1}{cos(\theta)}$

therefore

$cos(\theta)=\frac{1}{\sqrt{10}}$

step 2

Find $sin(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin(\theta)=tan(\theta)cos(\theta)$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

$tan(\theta)=3$

substitute

$sin(\theta)=(3)(\frac{1}{\sqrt{10}})$

$sin(\theta)=\frac{3}{\sqrt{10}}$

step 3

Find $cos(2\theta)$

we know that

$cos(2\theta)=2cos^2(\theta)-1$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

substitute

$cos(2\theta)=2(\frac{1}{\sqrt{10}})^2-1$

$cos(2\theta)=\frac{1}{5}-1$

$cos(2\theta)=-\frac{4}{5}$

Remember that

$sec(2\theta)=\frac{1}{cos(2\theta)}$

therefore

$sec(2\theta)=-\frac{5}{4}$

8 0

3 years ago