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3 years ago

What are 3 numbers whose product is 9,000

Mathematics

2 answers:

serg [7]3 years ago

6 0

1, 2, and 4500 I think.

kondor19780726 [428]3 years ago

5 0

3000 is your answer. 3000 x 3 is 9000. :)

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I will give brainlest please help should i write the answer differently? First answer gets brainlest

solmaris [256]

Answer:

15.6m

Step-by-step explanation:

FE is the hypotenuse, and we know the leg opposite of the angle, so we have to use the sin

sin = opposite/hypotenuse

hypotenuse * sin = opposite

hypotenuse = opposite / sin

FE = 10/0,64... = 15.6

5 0

3 years ago

Can Someone please answer this ?

Anna11 [10]

(2,0)
(-3,6)
(4, -20)

3 0

2 years ago

(8+3)n for n=6 help me please I'm not sure how to answer this problem how do I work this problem to get answer?

Andreas93 [3]

Answer:

54 ~ see below for explanation

Step-by-step explanation:

you're going to replace n with the 6 since n= 6

so (8+3)6

then you're going to add 8+3 in the parenthesis because of PEMDAS

(9)6

you're going to multiply 6 by 9 since 9 is in parenthesis (a number in parenthesis means multiply)

then you get 54 so the answer would be 54.

6 0

2 years ago

Using the point-slope formula, what is the equation of the line that passes through the points (1,5) and (0, 0)?

DerKrebs [107]

Answer:

y =5x

Step-by-step explanation:

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

(5 - 0) = m(1 - 0)

5 = m(1)

5 = m

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

y - 5 = 5(x - 1)

y - 5 = 5x - 5

y = 5x -5 + 5

y = 5x

7 0

2 years ago

Given that tan^2 theta=3/8,what is the value of sec theta?

algol [13]

Answer:

The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = $\frac{3}{8}$

Or, tanФ = $\sqrt{\frac{3}{8} }$

∵ tanФ = $\frac{Perpendicular}{Base}$

So, $\frac{Perpendicular}{Base}$ = $\sqrt{\frac{3}{8} }$

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( $\sqrt{3}$ )² + ( $\sqrt{8}$ )²

Or, Hypotenuse² = 3 + 8 = 11

Or, Hypotenuse = ( $\sqrt{11}$ )

Now SecФ = $\frac{Hypotenuse}{Base}$

or, SecФ = $\frac{\sqrt{11}}{\sqrt{8}}$ = $\sqrt{\frac{11}{8} }$

<u>Second Method</u>

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 + tan²Ф

or, Sec²Ф = 1 + $\frac{3}{8}$

Or, Sec²Ф = $\frac{11}{8}$

Or, SecФ = $\pm \sqrt{\frac{11}{8}}$

Hence The value of SecФ is $\pm \sqrt{\frac{11}{8}}$ . Answer

7 0

3 years ago

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