Is there a picture for the problem?
Answer:
I . class width is 3
ii. Class midpoints are 33,36,39,42,45,48,51.
iii. Class boundaries are: 31.5-34.5, 34.5-37.5, 37.5-40.5, 40.5-43.5, 43.5-46.5, 46.5-49.5, 49.5-52.5
Step-by-step explanation:
I. The class width is the difference between upper class boundary and lower class boundary.
ii. Class midpoints is the summation of upper and lower class limits, divided by 2.
iii. Class boundaries is the subtraction of 0.5 from the lower classe limits and the addition of 0.5 to upper class limits.
Answer:
rang is f(x)≥0
the domain is -∞<x<+∞
Step-by-step explanation:
the rang of this function is defined by c|ax+b|+k is f(x)≥0
1/2x + 42 = 4x
-1/2x -1/2x
------------------------
42 = 3.5x
/3.5 /3.5
------------------------
12 = x
the number is 12
explanation: 42 more than 1/2 of a number can be written as 1/2x + 42
four times a number can be written as 4x.
42 more than 1/2 of a number is equal to 4 times a number. So 1/2x + 42 = 4x.
Hope this helps :)
Answer:
you can decide if you want this answer or not :D
Step-by-step explanation:
1st , notice that our problem is about an eight part whole. I mean, the questions are around an object of 8 parts. so start thinking 1/8 ths
A) asks about P(7) ... they want to know.. how often the spinner will land on 7. so if it's totally random, 7 will happen just as likely as any of the other numbers so 7 will happen 1/8 th of the time
as a fraction it's 1/8 as a decimal it's 0.125 and as a percent it's 12.5 %
B) asks about P(2 or 6 ) [ btw, p here stands for probability ]
so it's 1/8 + 1/8 = 1/4 or one quarter of the time we would get a 2 or a 6
as a fraction it's 1/4 , as a decimal it's 0.25 and as a percent it's 25%
C) asks about P( greater than 4) or P( >4) so that's the whole left side of the circle :0
as a fraction it's 1/2 as a decimal it's 0.5 and as a percent it's 50%
D) P( not a 5) or P( ~=5) so every thing but a 5
as a fraction that's 7/8 as a decimal it's 0.875 and as a percent that 87.5 %
I'll take the odds on that last one to win the lottery plz :)
