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alina1380 [7]
3 years ago
10

What’s the graph function f(x) =4(1.5)^x

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

See below.

Step-by-step explanation:

Step 1. Find any zeroes.

(a) <em>y-intercept </em>

y = 4(1.5)^x     Let x = 0

  = 4(1.5)⁰

  = 4 × 1

  = 4

We have a <em>point at (0,4)</em>.

(b) <em>x-intercept </em>

    y = 4(1.5)^x     Let y = 0

    0 = 4(1.5)^x     Divide each side by 4

    0 = (1.5)^x        Take the log of each side

log0 = xlog1.5

log(0) is undefined. There is <em>no x-intercept. </em>

Step 2. Identify any asymptotes

y<em> </em>= 4(1.5)^x

y can never be negative, so the <em>x-axis is an asymptot</em>e.

Step 3. Plug in and plot a few points

Here's a table of a few points.

<u>  x      y   </u>

-6     0.4

-4     0.8

-2     1.8

-1     2.7

0    4.0

1     6.0

2    9.0

4  20.3

6  45.6

Step 4. Check the end behaviour.

y = 4(1.5)^x

As x ⟶ ∞, y ⟶ ∞.

As x ⟶ -∞, y ⟶ 0 .

Step 5. Draw a smooth line through the points.

Your graph should look something like the one below.

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Answer with explanation:

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→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

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