The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
yeah b
Step-by-step explanation:
took the test
Answer:
1.42 x 105
Step-by-step explanation:
The answer is C. 16/55 because P(Q and R) = P (Q) . P (R) (for independent events Q and R)
So, the prob. is 4/5 * 4/11 = 16/55 = D.
Answer:
8.30256
Step-by-step explanation:
Step 1: Write out expression

Step 2: Use BPEMDAS to evaluate




= 8.30256
And we have our answer!