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Stels [109]
3 years ago
14

The shortest path from point A to point B goes through a pond. To avoid

Mathematics
1 answer:
coldgirl [10]3 years ago
4 0
61.47 meters
You can use Pythagorean’s Theorem here which is a^2+b^2=c^2
Walking across would be the hypotenuse. So 23^2+57^2=c^2
529+3249=3778
And the sqrt of 3778 will be the answer which is about 61.47 meters
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Uma pessoa deseja restaurar seu veículo antigo e para isso deverá contratar serviços mecânico, de funilaria e de autoelétrica. P
Leni [432]

Answer:

CI=P*(1 + R/100)^18

A=(CI + P) = P(1+R/100)^18

13500/P=1(100+R/100)^18

A/P=(100+R/100)^18

A/P=(100+R/100)^18

A=13500$        as (750 * 18)

(13500)/P=(1 +1.15/100)18

(13500)/P=(1+1.15/100)18

13500=((1.0115)^18

P=R$10989.02

Step-by-step explanation:

CI=Compound Interest

A=Amount

P=Principal.

3 0
3 years ago
A motorboat left a harbor and traveled to an island at an average rate of 10 knots. The average speed on the return trip was 10
Illusion [34]

Answer:

A on edu2020

Step-by-step explanation:

5 0
3 years ago
Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
6 0
3 years ago
What is 2+2 <br> haha take all the points and mark me brainliest and like
Rainbow [258]

Answer:

4

Step-by-step explanation:

7 0
2 years ago
Solve the graph to find
Juliette [100K]

Answer:

Step-by-step explanation:

x=3            x=2.        x=1

y=1 *3        y=1 *2.       y=1 *1

y=1               y=1.       y=1

(3,1).            (2,1)        (1,1)

‘The others are the same. Probably you can use a calculator too

8 0
3 years ago
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