At 5 a.m., the temperature at an airport was −9.4°F . Six hours later, the temperature was 2.8°F .
1 answer:
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<u>Answer:</u>
A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.
<u>Solution:</u>
We need to show that the gradient of the curve at A is 1
Here given that ,
--- equation 1
Also, according to question at point A (b+1,0)
So curve at point A will, put the value of x and y
0=b+1-c --- equation 2
According to multiple rule of Differentiation,
so, we get
By putting value of point A and putting value of eq 2 we get
Hence proved that the gradient of the curve at A is 1.
Answer:
y+11=-(x-4)
Step-by-step explanation:
since the equation is perpendicular to y=4x-2, m=-1/4 (negative reciprocal). (x_1,y_1)=(4,-11), plug all the values into the equation y- y_1 = m(x-x_1) and we get y+11=-(x-4)