Question 1
cos(C) = adj/hyp
cos(C) = BC/AC
cos(C) = 15/17
Answer: Choice C) 15/17
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Question 2
sin(E) = opp/hyp
sin(E) = FD/DE
sin(E) = 24/25
So angle E is the answer
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Question 3
AC is the adjacent side to the given angle A = 33 degrees
AB = 14 is the hypotenuse
cos(angle) = adjacent/hypotenuse
cos(33) = x/14
14*cos(33) = x
x = 14*cos(33)
x = 11.741
x = 11.7
Answer: 11.7
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Question 4
x = length of board
cos(angle) = adj/hyp
cos(55) = 6/x
x*cos(55) = 6
x = 6/cos(55)
x = 10.46068
x = 10.5
Answer: 10.5
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Question 5
112 is the adjacent side to the given angle 62 degrees
x = height of building, which is the opposite leg
tan(angle) = opp/adj
tan(62) = x/112
112*tan(62) = x
x = 112*tan(62)
x = 210.641364
x = 210.6
Answer: 210.6
Answer:
I'd say A
Step-by-step explanation:
Reason: Because B and C are both having bands there and the cafeteria has the students popular opinion where there isn't band influence.
Answer:
Step-by-step explanation:
m = slope where
m = rise / run
rise = y2 - y1
run = x2 - x1
where
the given point P1 = (7, -12)
and is in the form of (x1,y1)
and
the given point P2 = (-9,36)
is in the form of (x2,y2)
then
m = ( y2 - y1 ) / ( x2 - x1 )
m = ( 36 - (-12) ) / ( -9 -7 )
m = ( 36 + 12 ) / ( - 16 )
m = 48 / - 16
m = - 3
the slope is negative 3
slope = - 3
Answer:
The length of PQ is <u>18</u> feet.
The length of PR is <u>18</u> feet.
The length of QR is <u>24</u> feet.
Step-by-step explanation:
A way to set an equation up for this problem is:
where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.
Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:
Don’t solve the whole equation, just solve the 
part of the equation, which is equal to 24. So the final equation is this:
Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).
Sorry for the long explanation.
But hope this helps and answers your question :)
Hey there!
We have 10 pieces of paper. The probability of drawing a 10 is 1/10. Therefore, if we were to draw ten times, the ten should probably be drawn once. If we multiplied our number of drawings by four (10*4=40), our outcome of seeing our slip with the ten should also quadruple and become four times. (1*4=4)
I hope that this helps! Have an awesome day!
