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3 years ago

Can sommeone please answer this

Mathematics

1 answer:

lukranit [14]3 years ago

3 0

Answer:

x= 8

z= 116 degrees

Step-by-step explanation:

the two given angle measures are vertical angles so they are equal to each other, the equation is: 12x-32 = 11x-24

simplify this to get: x= 8

plug the value of x into either of the given equations, I will use the first one: 12(8) - 32

this means that the angle of one of them is 64

and since z and 12x-32 make a straight angle (180 degrees)

you can subtract 64 from 180 to find z

this gives you 180-64 = 116

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How do you solve number 29? Please step by step

trapecia [35]

Answer:

a) Junnie walked farther than Maurice

b) Junnie walked .62 miles farther than Maurice

Step-by-step explanation: Because speed times time equals distance, to find how far each person traveled you multiply their speed and time.

Distance=speed×time

Junnie:

2.5hrs×3.2mph=8 miles

Maurice:

1.8hrs×4.1mph=7.38 miles

8-7.38=.62 (the difference between the two)

3 0

3 years ago

The two-way table shows the estimated number of students who will enroll in three area high schools next year. a 5-column table

mr Goodwill [35]

Answer:

A. 0.2

Step-by-step explanation:

First make the table.

10-grade 11-grade 12-grade Total

Woodson high school | 110 | 120 | 80 | 310 |

Valley high school | 180 | 150 | 120 | 450 |

Riverside high school | 160 | 140 | 200 | 500 |

Total | 450 | 410 | 400 | 1260 |

Question: In decimal form, to the nearest tenth, what is the probability that a randomly selected riverside high school student is in twelfth grade?

First, find 12-grade and riverside high school number. 200. Take the total lined up with total number, which is 1260, and divide 200 divided by 1260.

200/1260=0.2

The answer is 0.2.

Hope this helps!

If not, I am sorry.

6 0

2 years ago

Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.

Sedaia [141]

Answer:

Equations with one solution: $-2(x-3) = 2x-6$

Equations with no solution:

$6(x+5) = 6x+11\\5(x-2) = 5x-7$

Equations with infinite many solutions: $-3(x-4) = -3x+12$

Step-by-step explanation:

We will solve each equation to see if it has one solution, no solution or infinite many solutions.

An equation where the value of variable can be found has one solution.

An equation with no solution has both sides different.

An equation with infinite solution will have both sides equal after solution(number)

So,

Equation 1:

5(x-2) = 5x-7

$5(x-2) = 5x-7\\5x-10 = 5x-7\\5x-5x = -7+10\\0 = 3$

As both sides are not equal, equation has no solution.

Equation 2:

$-3(x-4) = -3x+12\\-3x+12 = -3x+12\\-3x+3x = -12+12\\0=0\\$

As both sides are equal the equation has infinite many solutions.

Equation 3:

$-2(x-3) = 2x-6\\-2x+6 = 2x-6\\-2x-2x = -6-6\\-4x = -12\\\frac{-4x}{-4} = \frac{-12}{-4}\\x = 3$

As x=3, the equation has only one solution.

Equation 4:

$6(x+5) = 6x+11\\6x+30 = 6x+11\\6x-6x+30 = 11\\30 =11$

The equation has no solution.

Hence,

Equations with one solution: $-2(x-3) = 2x-6$

Equations with no solution:

$6(x+5) = 6x+11\\5(x-2) = 5x-7$

Equations with infinite many solutions: $-3(x-4) = -3x+12$

6 0

3 years ago

Wht is the soulution of the proprtion 5/16=30/y

Anit [1.1K]

I don’t knowwwwwwwwwwwww

3 0

3 years ago

A rep hockey team has two goalies. Goalie A has a save percentage of 0.92 and Goalie B has a save percentage of 0.89. If goalie

hjlf

Answer:

a) 0.9125

b) 0.756

c) 0.314

Step-by-step explanation:

The save percentage of Goalie A = 0.92

The save percentage of Goalie B = 0.89

The percentage of the games Goalie A plays = 75 percent

The percentage of the games Goalie B plays = 25 percent

a) The probability that a save has been made by either Goalie A or Goalie B

Therefore we get;

The probability that Goalie A made a save, P(A) = 0.92 × 0.75 = 0.69

The probability that Goalie B made a save, P(B) = 0.89 × 0.25 = 0.2225

For mutually exclusive events, we have;

P(A) or P(B) = P(A) + P(B)

∴ P(A) or P(B) = 0.69 + 0.2225 = 0.9125

The probability that a save has been made by either Goalie A or Goalie B, P(A) or P(B) = 0.9125

b) Where there are 10,000 attempts, made evenly in all games, we have;

The number of attempts made with Goalie A playing = 10,000 × 0.75 = 7,500

The number of saves Goalie A makes = 0.92 × 7,500 = 6,900

The number of saves for 10,000 attempt = (P(A) or P(B)) × 10,000 = 0.9125 × 10,000

The number of saves for 10,000 attempt = 9,125

∴ The probability that Goalie A saves = 6,900/9,125 ≈ 0.756

c) Out of the 2,500 attempts at Goalie B, the number of goals let in is given as follows;

P(Goal B) = 2,500 - 2,500 × 0.89 = 275

The number of goals let in by Goalie A, we have;

P(Goal A) = 7,500 - 7,500 × 0.92 = 600

Therefore, the total number of goals let in = 300 + 275 = 875

The probability that the goals was let in by Goalie B = 275/875 = 11/35 ≈ 0.314.

7 0

3 years ago