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Musya8 [376]
3 years ago
7

You measure 20 dogs' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 11.5 ou

nces. Based on this, construct a 95% confidence interval for the true population mean dog weight.
Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0

95% confidence interval would be (58.96, 69.04).

Step-by-step explanation:

Since we have given that

Number of dogs' weight = 20

Mean = 64 ounces

Standard deviation = 11.5 ounces

We need to find the 95% confidence interval.

So, z = 1.96

so, interval would be

\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=64\pm 1.96\times \dfrac{11.5}{\sqrt{20}}\\\\=64\pm 5.04\\\\=(64-5.04,64+5.04)\\\\=(58.96,69.04)

Hence, 95% confidence interval would be (58.96, 69.04).

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Answer:

The change division should put the unit to be dispensed with as an afterthought inverse of where it happens in the first inquiry.

540 inches * (1 yard/36 inches)

The inches best and base drop, abandoning you with the outcome in yards.

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Isabel began training for a marathon by running 63 miles during her first week. Each week, she increased the distance she ran by
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10% of 63 is 6.3 so 63+6.3=69.3

Step-by-step explanation:

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How do I solve this math problem?<br><br> M <br> — = -3 <br> 4
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Line FG goes through the points (4,9) and (1,3). Which equation represents a line that is perpendicular to FG and passes through
stiks02 [169]

Answer:

x + 2y= 2

Step-by-step explanation:

Given

Points:

F = (4,9)

G = (1,3)

Required

Determine the equation of line that is perpendicular to the given points and that pass through (2,0)

First, we need to determine the slope, m of FG

m = \frac{y_2 - y_1}{x_2 - x_1}

Where

F = (4,9) --- (x_1,y_1)

G = (1,3) --- (x_2,y_2)

m = \frac{3 - 9}{1 - 4}

m = \frac{- 6}{- 3}

m =2

The question says the line is perpendicular to FG.

Next, we determine the slope (m2) of the perpendicular line using:

m_2 = -\frac{1}{m}

m_2 = -\frac{1}{2}

The equation of the line is then calculated as:

y - y_1 = m_2(x - x_1)

Where

m_2 = -\frac{1}{2}

(x_1,y_1) = (2,0)

y - 0 = -\frac{1}{2}(x - 2)

y  = -\frac{1}{2}(x - 2)

y  = -\frac{1}{2}x + 1

Multiply through by 2

2y = -x + 2

Add x to both sides

x + 2y= -x +x+ 2

x + 2y= 2

Hence, the line of the equation is x + 2y= 2

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