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snow_tiger [21]

3 years ago

14

You have recorded your car mileage and gasoline use for 5 weeks. Estimate the number of miles you can drive on a full 15-gallon

tank of gasoline.

1 answer:

Zepler [3.9K]3 years ago

4 0

Answer:

I think its 21.6 or 22 (Mostly 21.6 though) Sorry if its not right but i'm mostly sure of it like this!

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The marked price of

Tju [1.3M]

Answer:

MP = Rs. 1500

SP = Rs. 1230

Step-by-step explanation:

Let the Cost Price (CP) be x

<u>Then Market Price (MP):</u>

MP = x+ 20% = 1.2x

<u>Discounted Selling Price (SP):</u>

SP = MP - 18% = 0.82*1.2x = 0.984x

<u>Since the difference between CP and SP is Rs.20:</u>

x - 0.984x = 20
0.016x = 20
x= 20/0.016
x = 1250

<u>Then:</u>

MP = 1.2*1250= Rs. 1500

and

SP = 1500*0.82 = Rs. 1230

3 0

3 years ago

Holly's fitness tracker shows how many

Dafna11 [192]

Holly would have to climb 92 flights of stairs in the fifth week

5 0

3 years ago

The equation y 4.9t 2 3.5t 2.4 relates the height y in meters to the elapsed time t in seconds for a ball thrown downward at 3.5

tamaranim1 [39]

Answer:

$t \approx 0.43\,s$

Step-by-step explanation:

The vertical displacement function is $y(t) = -4.9\cdot t^{2}-3.5\cdot t + 2.4$ , where $y(t)$ is measured in meters and $t$ in seconds. Ball hits the ground when $y(t) = 0$ . That is:

$-4.9\cdot t^{2}-3.5\cdot t + 2.4 = 0$

Whose roots can be found by using the General Formula for Second-Order Polynomials:

$t_{1,2} = \frac{3.5\pm \sqrt{(-3.5)^{2}-4\cdot (-4.9)\cdot (2.4)} }{2\cdot (-4.9)}$

Solutions of this polynomial are:

$t_{1} \approx 0.43\,s,t_{2} \approx -1.14\,s$

Only the first root is physically consistent.

3 0

3 years ago

At 3:30 p.m., Berto’s train was 34 miles past the egg farm, traveling at an average speed of 85 miles per hour. At the same time

timurjin [86]

E=egg farm

x=distantce between the Berto´s trains and the meeting point.

t=time where the trains meet up

⇒110 miles/h ⇒85miles/h

[---------------------------E----------------------]-------------------------------------X

[............12 miles.......][........34 miles.....][------------ x ----------------------]

distance between Berto´s train and Eduardo´s train=

=12 miles+34 miles=46 miles.

S=d/t ⇒d=S*t

S=seed

d=distance

T=time

Eduardo´s train;

46 miles+x=t*110 miles/h ⇒x=t*110 miles/h-46 miles (1)

Berto´s train;

x=t*85 miles/h (2)

With the equations (1) and (2) we suggest this system equations:

x=t* 110 miles/h-46 miles

x=t*85 miles/h

we solve this system equiations :

t*110 miles/h-46 miles=t*85 miles/h

110t miles/h-85t miles/h=46 miles

25 t miles/h=46 miles

t=46 miles/25 miles/h=1,84 hour (≈1 hour, 50 minutes, 24 seconds)

x=t*85 miles/h=156,4 miles

Solution: 1,84 hour

3 0

3 years ago

Read 2 more answers

Hana buys a new dress for $40. how much does she pay if there is a 7% tax

Rzqust [24]

Answer:

$42.80

Step-by-step explanation:

We can set up an equation to solve this as such

$40*1.07=42.80$

6 0

2 years ago