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3 years ago

What is 12.50 as a mixed number?

Mathematics

1 answer:

antoniya [11.8K]3 years ago

7 0

12 1/2 is 12.50 as a mixed number

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Which of the following tables shows a proportional relationship?<br>A)<br>B) <br>Please Help ASAP

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3 years ago

at 5pm two hip started sailing toward each other from ports which were 300 miles apart at average rates of 20 and 25 mes per hou

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If the average rates were 20 and 25 miles per hour, then together they cover 45 miles of the distance they are separated by per hour. The ships will be 30 miles apart when 270 miles have been covered, so it takes 270/45=6 hours to cover the distance. 6 hours after 5 PM is 11:00 PM.

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3 years ago

Please find the slope of (-2, 4) and (3, -5)

DIA [1.3K]

Answer:

The slope of the line = m = -9/5

Step-by-step explanation:

Given the points

(-2, 4)

(3, -5)

Determining the slope between (-2, 4) and (3, -5)

(x₁, y₁) = (-2, 4)

(x₂, y₂) = (3, -5)

Using the formula

Slope = m = [y₂ - y₁] / [x₂ - x₁]

= [-5 - 4] / [3 - (-2)]

= [-9] / [3 + 2]

= -9/5

Thus, the slope of the line = m = -9/5

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3 years ago

the pet store sells bags of pet food. there are 4 bags of cat food. one sixth of the bags of food are bags of cat food. how many

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28 bags if you include the cat food (which you would)

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3 years ago

Read 2 more answers

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

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3 years ago