<u>the question is </u> Calculate the value of the copper in the coin
Step 1
Find the volume of the coin
we know that
the volume of a cylinder is equal to

where
r is the radius of the coin
h is the thickness of the coin
in this problem we have
Diameter=19 mm=1.9 cm
r=D/2------> r=1.9/2=0.95 cm
h=1.5 mm=0.15 cm
substitute the values in the formula

Step 2
<u>Find the mass of copper in the coin</u>
we know that
the density is equal to

Solve for the mass

we have

substitute in the formula

Step 3
<u>Find the cost</u>
we know that
the market price of the copper is $2.15 per pound
1 pound=453.592 grams
convert gram to pounds
3.785 gr=3.785/453.592=0.0083 pounds
0.0083*$2.15=$0.018=$0.02
therefore
<u>the answer is</u>
$0.02
so it is compounded 4 times in a year in 4 years we can take it as 16 terms
a=6700(1+3.3/100)^16
a=6700(1+33/1000)^16
a=6700(1000/1000 + 33/1000)^16
a=6700(1.033)^16
a=6700*1.681144887891022
a=6700*1.6811
a=11263.23
2x + 4y - 2x - 3y = 22 - 50
y = -28
substitute into the 1st equation to find x
Answer:
greater
Step-by-step explanation: