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3 years ago

Find the area of a sector of a circle whose radius is 16 cm and whose central angle is

Mathematics

1 answer:

valentinak56 [21]3 years ago

6 0

Answer:

1πcm

Step-by-step explanation:

do you have another question to ask pls if you have ask

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Bonjour tout le monde j'ai des exercices de maths que je n'arrive pas pouvez vous m'aidez svp c'est urgent c'est pour demain mer

dedylja [7]

Je regrette je ne comprends pas très bien

4 0

3 years ago

A circle with circumference 6 has an arc with a 60° central angle.

erica [24]

Answer:

length of an arc = 1unit

Step-by-step explanation:

given that the circumference of a circle = 6

central angle = 60

length of the arc =?

recall that the circumference of a circle = 2πr

6 = 2πr

r = 6/2π

now to calculate the length of an arc

recall,

length of an arc = 2πr(Ф/360)

length of an arc = 2π(6/2π) × 60/360

length of an arc = 6 × 60/360

length of an arc = 360/360

length of an arc = 1unit

therefore the length of the arc whose circumference is 6 and arc angle is 60° is evaluated to be 1unit

5 0

3 years ago

Line segment AB is the diameter of circle C. If the endpoints of the diameter are (3, -4) and (7,2), what are the coordinates of

dimulka [17.4K]

Answer:

(5, -1)

Step-by-step explanation:

You find the center of both the coordinates. For the x axis: 3+7 = 10. 10/5=2. For the y axis: -4+2=-2. -2/2 = -1. Put them together and get the answer! :)

5 0

3 years ago

The area of a rectangular-shaped garden can be no more than 64 square feet. If the length of the garden is 16 feet, what could b

Klio2033 [76]

Answer:

4 square feet

Step-by-step explanation:

Area = Length * Width

64 = 16 * W.

W = 4.

So, 4 square feet.

Mark me as Brainliest if this is correct! I really appreciate it! :D

8 0

3 years ago

Can anyone help me solve a trigonomic identity problem and also help me how to do it step by step?

dusya [7]

$\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\\\\
-------------------------------\\\\$

$\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\
-------------------------------\\\\
\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1
\\\\\\
\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies 
\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}$

$\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}
\\\\\\
\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}
\\\\\\
\cfrac{1}{sin(\theta )}\implies csc(\theta )$

7 0

3 years ago