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mylen [45]
3 years ago
11

last year, ahmad opened an investment account with $6500. at the end of the year, the amount in the account had increased by 22.

8%. how much is this increase in dollars? how much money was in his account at the end of last year?​
Mathematics
2 answers:
azamat3 years ago
8 0

Answer:

$1,430, $7,930

Step-by-step explanation:

Start:  $6,500

End:  $6,500 + 0.228($6,500) = 1.22($6,500) = $7,930

The increase is $7,930 - $6,500 = $1,430

and at the end of the year Ahmad would have $7,930 in his account.

guapka [62]3 years ago
8 0

By the end of last year, there was a 6500(22.8/100)= 1482 increase in dollars.

There was 7982 dollars at the end of last year.

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Match the expression with its name.
TiliK225 [7]

Answer:

\large\boxed{10x^2-5x+10\ -\ \bold{quadratic\ trinomial}}

Step-by-step explanation:

\text{quadratic trinomial}\ -\ ax^2+bx+c\\\\\text{cubic monomial}\ -\ ax^3\\\\\text{not a polynomial}\ -\ \dfrac{a}{x}\\\\\text{fourth-degree binomial}\ -\ ax^4+bx

10x^2-5x+10\\\\\text{the highest power of variable (x) is 2}\to \boxed{x^2}\ \to\ \bold{quadratic}\\\\\text{polynomial has 3 terms}\ \to\ \boxed{10x^2,\ -5x,\ 10}\ \to\ \bold{trinomial}

4 0
3 years ago
What is the perimeter of a square whose diagonal is 3 radical 2
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7 0
3 years ago
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Zinaida [17]

Answer:

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Explanation:

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DerKrebs [107]

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