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Anettt [7]
3 years ago
6

Match the expression with its name.

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

\large\boxed{10x^2-5x+10\ -\ \bold{quadratic\ trinomial}}

Step-by-step explanation:

\text{quadratic trinomial}\ -\ ax^2+bx+c\\\\\text{cubic monomial}\ -\ ax^3\\\\\text{not a polynomial}\ -\ \dfrac{a}{x}\\\\\text{fourth-degree binomial}\ -\ ax^4+bx

10x^2-5x+10\\\\\text{the highest power of variable (x) is 2}\to \boxed{x^2}\ \to\ \bold{quadratic}\\\\\text{polynomial has 3 terms}\ \to\ \boxed{10x^2,\ -5x,\ 10}\ \to\ \bold{trinomial}

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Randy and Molly are selling pies for a school fundraiser customers can buy blueberry pies and pumpkin pies brandy sold 6 blueber
QveST [7]

Answer:

One blueberry pie = $7

One pumpkin pie = $16

Step-by-step explanation:

Since there are two variables in this problem - the cost of blueberry pie and the cost of pumpkin pie, we can set up a system of equations to solve.  Since Brandy sold 6 blueberry pies and 4 pumpkin pies for $106, our first equation is:   6b + 4p = 106.

Molly sold 6 blueberry and 3 pumpkin for $90, so the second equation is: 6b + 3p = $90.

We can use elimination to add the two equations together and eliminate one variable while we solve for the other:

6b + 4p = 106

6b + 3p = 90

In order to eliminate a variable, you can multiply the first equation by -1:

-1(6b + 4p = 106) = -6b - 4p = -106

Add<u> 6b + 3p = 90</u>

-p = -16, so p = 16

Now, solve for b:  6b + 3(16) = 106 or 6b + 48 = 90

Subtract 48 from both sides:  6b + 48 - 48 = 90-48

Divide by 6:  6b/6 = 42/6

Solve for b: b = 7


3 0
3 years ago
McKenna earns $12 per hour mowing her grandmother yard.
Elden [556K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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yulyashka [42]

Step-by-step explanation:

Let p and h represent pay and hours worked respectively,

p = kh

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Hope it helps! :)

3 0
2 years ago
Explain why it is helpful to know the basic function shapes and discuss some ways to remember them.
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<h3>Explain why it is helpful to know the basic function shapes and discuss some ways to remember them. </h3>
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