Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
I was going to answer but she gave you the answer sooo
25 add them up Your welcome
Answer:
25, 90, and 65
Step-by-step explanation:
so the measures have to add up to 180, because it's a triangle, and we know 25 and 90 ( the box corner thing means that angle is 90) so we add 25 and 90 to get 115, and then we subtract 115 from 180, which gets us 65.
Answer:
x= -1/21
Step-by-step explanation:
21x + 11 - 5 = 5
21x + 6 = 5
(-6 each side)
21x = -1
(divide 21 each side)
x= -1/21
