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Elan Coil [88]
4 years ago
11

Simplify the following 1/3 + 14/5 - (-7/10)

Mathematics
2 answers:
Nina [5.8K]4 years ago
5 0

Answer:

\frac{1}{3}  +  \frac{14}{5}  - ( -  \frac{7}{10} ) \\  \frac{1}{3}  +  \frac{14}{5}  +  \frac{7}{10}  \\  \frac{50}{150}  +  \frac{420}{150}  +  \frac{105}{150}  \\  =  \frac{575}{150}  \\  =  \frac{115}{30}  \\  = 3 \frac{25}{30}

Nataliya [291]4 years ago
3 0

Answer:

Exact form: \frac{23}{6}

Decimal Form:  3.83

Mixed Number Form: 3\frac{5}{6}

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5 sevenths times 3 fifths
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It's actually really simple! All you gotta do is write down the 2 fractions and multiply both the denominators and numerators. After you get the answer, just simply the fraction and you have your final answer!\frac{5}{7} *  \frac{3}{5} =  \frac{15}{35}= \frac{3}{7}
8 0
4 years ago
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Simplify the given expression below: (−3 + 2i) ⋅ (2 + i) A. −8 + i B. −6 + 3i C. −3 + 4i D. −1 + 2i
oksian1 [2.3K]

Answer:

-8 + i

Step-by-step explanation:

(-3 + 2i) * (2 + i)

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7 0
3 years ago
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AURORKA [14]

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= (1/3) π (10 cm)². 16 cm

= (1/3) π (100 cm²). 16 cm

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4 years ago
Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10
Iteru [2.4K]

Answer:

The number of bacteria B after d days is given by

B = B_0 (3)^{\frac{1}{10} d}

where B_0 is the initial number of bacteria.  

Step-by-step explanation:

The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

B = (B_0 *3)*3

after the 3rd day,

B =( B_0 *3*3)*3

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

where n is is the <em>n</em>th 10-days.

Since, n is 10 days, we have

d =10n

or

n =\dfrac{1}{10}

Substituting that into B = B_0 (3)^n, we get:

\boxed{ B = B_0 (3)^{\frac{1}{10} d}}

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boyakko [2]

Answer: A

Step-by-step explanation:

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