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Katarina [22]
3 years ago
11

Peter earns $11,250 per year, of which 31% is spent on food. What amount is spent yearly on food?

Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

Total amount spend by Peter on food is $3487.5.

Step-by-step explanation:

Given information:

Income of Peter = $11,250 per year

Percent of income that he spends on food = 31%

We need to find the total amount that he spends yearly on food.

Total amount spent by peter on food is 31% of his income, i.e. 11,250.

\text{Amount spend on Food}=11250\times \frac{31}{100}

\text{Amount spend on Food}=3487.5

Therefore total amount spent by Peter on food is $3487.5.

Alex_Xolod [135]3 years ago
3 0

Answer:

$7762.5

Step-by-step explanation:

31% is spent on food.



Subtract that from his income of 100%


you get 69%


Multiply 69% by his income, and you get $7762.5

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(3.) If it costs $4.20 per square foot to installthe deck, what is the cost for plan A? PlanB?
Yuri [45]

Answer:

Step-by-step explanation:

I have reproduced a diagram of the question in the attachment.

To do a price comparison, we simply find the areas of both the deck and garden in Plan A and Plan B.

In Plan A,

Deck Measures 18 feet by 25 feet

Garden measures 9 feet by 12 feet

Area of Garden = 12 X 9 =108 square feet

Area of Deck (in Gray) = (18 X 25) - (12 X 9) =450-108 =342 square feet

Cost of Garden =$1.40 X 108=$151.2

Cost of Deck = $4.20 X 342=$1436.4

Total Cost for Plan A= $151.2+ $1436.4=$1587.6

In Plan B

Deck Measures 16 feet by 20 feet

Garden has a radius of 5 feet

Area of Garden = =\pi r^{2}=  \pi X5 X 5=78.5 square feet

Area of Deck (in Gray) = (16 X 20) - ( \pi X5 X 5) =320-78.5 =241.5 square feet

Cost of Garden =$1.40 X 78.5=$109.9

Cost of Deck = $4.20 X 241.5=$1014.3

Total Cost for Plan B= $109.9+ $1014.3=$1124.2

Total Cost for Plan A=$1587.6

Total Cost for Plan B=$1124.2

Plan B is less expensive by $1587.6-$1124.2= $463.4

5 0
3 years ago
Multiplicación Qué me de 300
Goshia [24]
150x2=300 100x3=300
5 0
4 years ago
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Please help! Thank you.
lbvjy [14]

Answer:

Step-by-step explanation:

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3 0
3 years ago
–4(5x)<br> simplify .......
Monica [59]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
The correlation between the height and weight of children aged 6 to 9 is found to be about r = 0.8. Suppose we use the height x
Andrew [12]

Answer:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}

The value of r is always between -1 \leq r \leq 1

And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:

r^2 = 0.8^2 = 0.64

So then the best conclusion for this case would be:

c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.

Step-by-step explanation:

For this case we know that the correlation between the height and weight of children aged 6 to 9 is found to be about r = 0.8. And we know that we use the height x of a child to predict the weight y of the child

We need to rememeber that the correlation is a measure of dispersion of the data and is given by this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}

The value of r is always between -1 \leq r \leq 1

And we have another measure related to the correlation coefficient called the R square and this value measures the % of variance explained between the two variables of interest, and for this case we have:

r^2 = 0.8^2 = 0.64

So then the best conclusion for this case would be:

c. the fraction of variation in weights explained by the least-squares regression line of weight on height is 0.64.

3 0
3 years ago
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