<span>The numbers are 4 and 7
j^2+k^2=65
4^2+7^2=65
16+49=65
65=65
hope i helped</span>
Answer:
a. attached graph; zero real: 2
b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Step-by-step explanation:
p(x) = x³ + 4x² + 6x - 36
a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.
p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0
b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.
2 | 1 4 6 -36
1 6 18 0
x² + 6x + 18 = 0
Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²
√Δ = 6i
x = -6±6i/2 = 2(-3±3i)/2
x' = -3-3i
x" = -3+3i
p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
X + y = 1.....multiply by -2
2x - 3y = -30
-----------------
-2x - 2y = -2 (result of multiplying by -2)
2x - 3y = -30
----------------add
-5y = -32
y = -32/-5
y = 32/5 or 6.4 <===
Answer:
Hope this helps. If not let me know and I'll explain it better
Answer:
9 times
Step-by-step explanation:
I took 54 and divided it by six and got nine