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3 years ago

PLEASE HELP!!! Solving equations with substitution! I don't really know how to solve it.

Mathematics

2 answers:

Kipish [7]3 years ago

8 0

Answer:

x = 1

y = 2

Step-by-step explanation:

y = 2x

-6x + 6y = 6

-6x + 6(2x) =6 Substitute the fist equation for the value of y

-6x + 12x = 6 Combine like terms

6x = 6 divide

x = 1

Then, substitute the value of x in the equation for y

y = 2x y = 2(1)

y = 2

babunello [35]3 years ago

6 0

<h2>Steps:</h2>

So with using the substitution method, to be able to do so you must have one of the equations isolated with one of the variables. In this case, we see that the first equation has the y variable isolated. Now with this, we are going to substitute y in the second equation for 2x since y = 2x:

$-6x+6(2x)=6$

From here, we can solve for x:

$-6x+6(2x)=6\\-6x+12x=6\\6x=6\\x=1$

Since we have the x-value, substitute x for 1 into either equation to solve for y as such:

$y=2*1\\y=2\\\\-6(1)+6y=6\\-6+6y=6\\6y=12\\y=2$

<h2>Answer:</h2>

In short:

x = 1
y = 2

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2 years ago

The commuting time for a student to travel from home to a college campus is normally distributed with a mean of 30 minutes and a

Rainbow [258]

Answer:

0.1587

Step-by-step explanation:

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3 years ago

6x - 2(x + 2) > 2 - 3(x+3)<br><br>Solve the inequality <br><br>plz help

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Answer:

x > -3/7

Step-by-step explanation:

6x - 2(x + 2) > 2 - 3(x + 3)

Distribute the two and three inside the parenthesis.

6x - 2x - 4 > 2 - 3x - 9

Combine like terms.

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Add 4 to both sides.

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r-ruslan [8.4K]

Answer:

c) 0.932

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(0.932 ,1.071)

Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

<u>The 99% confidence intervals are given by</u>

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )$

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tₐ = 2.0322

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$(1.01 - 2.0322 \frac{0.18}{\sqrt{35} } , 1.01+2.0322 \frac{0.18}{\sqrt{35} } )$

( 1.01 - 0.06183 , 1.01+0.06183)

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<u>Final answer</u>:-

<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>

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