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jenyasd209 [6]
3 years ago
5

If a child's knowledge of the alphabet is limited to the letters a, b, c, i, and e, and if the child writes two letters at rando

m (assume the child may write the same letter twice), what is the probability that one is a vowel and the other is a consonant? A- 6/25 B- 12/25 C- 4/5
Mathematics
2 answers:
Soloha48 [4]3 years ago
7 0
I know that A is incorrect because i tried that answer and it marked me wrong hope this helps u a lil  <span />
sweet [91]3 years ago
6 0
A- 6/25 you can use A 4 times the other letters you can ether use 2 time or 1 time.
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Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle
Whitepunk [10]

Answer:

(6\sqrt{3},\,\frac{5\pi}{6})

Step-by-step explanation:

The radius  r  can be found from the relationship

 r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}

See the attached image.

7 0
3 years ago
The initial number of views for a certain website was 15. The number of views is growing exponentially at a rate of 22% per week
Oksi-84 [34.3K]

t he number of views expected to be four weeks from now can be calculated using the equation:

F = P ( 1+i)^n

Where F is the future views

P is the present views

i is the percent increase in views

n is the number of weeks

F = 15 ( 1+ 0.22)^4

F = 33 views

8 0
3 years ago
Read 2 more answers
LCM of two numbers is 1134 and HCF is 18. if one of the numbers is 162, find the other. number.<br>​
Brilliant_brown [7]
<h3>Answer:  126</h3>

=====================================================

Work Shown:

Let x and y be the two numbers.

We're given x = 162 and the variable y is unknown.

We're also given LCM = 1134 and HCF = 18

So,

LCM = (x*y)/HCF

1134 = 162*y/18

1134 = (162/18)y

1134 = 9y

9y = 1134

y = 1134/9

y = 126

The other number is 126

---------------------

Notice that

  • 162 = 18*9
  • 126 = 18*7

showing that 18 is the highest common factor (HCF) of the numbers 162 and 126. This partially confirms the answer.

Now let,

  • A = multiples of 162
  • B = multiples of 126

So,

  • A = 162, 324, 486, 648, 810, 972, 1134, 1296, ...
  • B = 126, 252, 378, 504, 630, 756, 882, 1008, 1134, 1260, ...

We see that 1134 is in each list of multiples and the smallest such common item. So the lowest common multiple (LCM) of 162 and 126 is 1134. This helps fully confirm the answer.

7 0
2 years ago
Write the 3 digit number that answers the riddle? I have the same hundreds digit as the ones digit. The value of my tens digit i
jok3333 [9.3K]
<span>The answer is 454. Since the value of the ones digit is 4, the last digit is a 4. Next, since the ones digit is the same as the hundreds digit, the first digit would be 4. Finally, the middle digit is the tens place and would be 5 since the tens digit is 50.</span>
4 0
3 years ago
Read 2 more answers
Please answer ASAP XD​
ivolga24 [154]
A. Good luck with your exam
7 0
3 years ago
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