Question

What is Perimeter of triangle ABC?

Answer 1

Considering they are congruent
if 7x-19=2x+11
how much is 6x-8

7x-19=2x+11
7x=2x+30
7x-2x=30
5x=30
X=6

6x-8=
(6*X)-8=
(6*6)-8=
36-8=
28

therefore
BC= 28
2x+11
(2*6)+11
12+11
23

23+28+24=75
therefore the perimeter is 75

hope you found this helpful, brainliest if possible please

Answer 2

ΔABC and ΔFEG are congruent. Therefore we have the equation:

7x - 19 = 2x + 11      add 19 to both sides

7x = 2x + 30     subtract 2x from both sides

5x = 30     divide both sides by 5

x = 6

AB = 24

AC = 2x + 11 → AC = 2(6) + 11 = 12 + 11 = 23

BC = 6x - 8 → BC = 6(6) - 8 = 36 - 8 = 28

The perimeter of ΔABC = 24 + 23 + 28 = 75

Answer: 75 feet