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2 years ago

What is the value of y in the solution to the system of equations?

Mathematics

1 answer:

Nana76 [90]2 years ago

4 0

The value of y is positive 8

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Solve x in 2|x+ 6| + 9 = 19

xenn [34]

Answer: x=-1

Step by step:

2|x+6|+9=19

Subtract 9 from both sides.

2|x+6|=10

Divide both sides by 2

|x+6|=5

Use the definition of absolute value.

x+6=5

Subtract 6 on both sides

x=-1

Hope this helped! :)

5 0

1 year ago

Read 2 more answers

How many terms are in the expression shown below?

german

The answer would be B

a2 = 1

ab=2

8b and b2=3

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2 years ago

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7: -5 = 0.25(4 + 20r) - 8r

Nonamiya [84]

The answer is r = 2. hope this helps :)

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2 years ago

Combine the like terms to create an equivalent expression _4p+(_6p)

Juli2301 [7.4K]

Xxxxxxxxxxxxxxxxxx，，，，，

5 0

2 years ago

What are the zeros for the function

Greeley [361]

The zeroes of the function are $x = -3, \ \ x =2\sqrt{ 3}i, \ \ x =-2\sqrt{ 3}i$ .

Solution:

Given function:

$f(x)=x^{3}+3 x^{2}+12 x+36$

<u>To find the zeros of the function:</u>

⇒ f(x) = 0

$\Rightarrow x^{3}+3 x^{2}+12 x+36=0$

$\Rightarrow (x^{3}+3 x^{2})+(12 x+36)=0$

Take x² as common in first bracket and take 12 as common in 2nd bracket.

$\Rightarrow x^2(x+3 )+12( x+3)=0$

Now, take common term (x + 3) outside.

$\Rightarrow (x+3 ) (x^2+12)=0$

<em>Using zero factor principle, If ab = 0 then a = 0 or b = 0.</em>

$x+3=0, \ \ x^2+12=0$

x = –3

$x^2+12=0$

x² = –12

x² = 2² × 3 × –1

Taking square root on both sides, we get

$\sqrt{x^2} =\pm\sqrt{2^2\times 3\times -1}$

$x =\pm2\sqrt{ 3\times -1}$

we know that $\sqrt{-1} =i$ .

$x =\pm2\sqrt{ 3}i$

$x =2\sqrt{ 3}i, \ \ x =-2\sqrt{ 3}i$

Hence the zeroes of the function are $x = -3, \ \ x =2\sqrt{ 3}i, \ \ x =-2\sqrt{ 3}i$ .

7 0

2 years ago