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2 years ago

Who knows about ratios

Mathematics

1 answer:

Kaylis [27]2 years ago

5 0

I can help you. Just post the question

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In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee

kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that $x^{2} =pz$

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles

and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

$\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}$

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

$\frac{x}{z}= \frac{p}{x}$

Cross multiply

$x^{2}=pz$

Hence proved.

7 0

3 years ago

Pls help me thanks so much

Igoryamba

Answer:

I beileve its no

Step-by-step explanation:

4 0

2 years ago

Hector is opening a bakery. He plans to start by selling cakes. It costs him $4 for each cake, $1.75 per box for the cakes, and

tatiyna

Answer:

Step-by-step explanation:

because if you add the numbers up you will get the answer easy :)

4 0

2 years ago

Read 2 more answers

What are the answers I need help ?

olchik [2.2K]

Answer:

I can't see -_-

Step-by-step explanation:

I can't -_-

7 0

3 years ago

Solve the differential equation.<br><br> (y^2 + xy^2)y' = 1

stira [4]

$(y^2 + xy^2)y' = 1 \ \Rightarrow\ (y^2 + xy^2)\frac{dy}{dx}= 1 \ \Rightarrow\\ \\
y^2(1 + x) \frac{dy}{dx} = 1 \ \Rightarrow\ y^2 dx = \frac{dx}{1 + x}\ \Rightarrow \\ \\
\int y^2 dx =\int \frac{dx}{1 + x} \ \Rightarrow\ \frac{1}{3}y^3 = \ln|1+x| + C\ \Rightarrow \\ \\
y^3 = 3 \ln|1 + x| + 3C\ \Rightarrow\ y = \sqrt[3]{3\ln|1+x| + K},\ \text{where $K = 3C$}
$

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2 years ago