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irakobra [83]
2 years ago
8

Maths Question involving factorising.

Mathematics
1 answer:
Bumek [7]2 years ago
6 0

Answer:

(x-1)(x+7)

Step-by-step explanation:

x = 1

x = -7

These are the roots found using the quadratic formula.

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What is 3,482,000,000 in scientific notation?
Volgvan
3.482×10^9
Imagine the decimal at the end of the last 0 and move it 9 places to the left
5 0
3 years ago
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The cost of 4 belts and 5 ties is $247. Each time costs 3 times as much as a belt. What us the total cost of 1 belt and 1 tie
Makovka662 [10]

Answer:

The total cost of 1 belt and 1 tie is $13 and $39 respectively.

Step-by-step explanation:

Given that,

The cost of 4 belts and 5 ties is $247.

Each tie costs 3 times as much as a belt.

Let the cost of a belt is x and that of a tie is y.

ATQ,

4x + 5y = 247 ...(1)

y = 3x ....(2)

Put the value of y from equation (2) in equation (1)

4x + 5(3x) = 247

4x + 15x = 247

19x = 247

x = 13

Put the value in equation (2)

y = 3x

= 3(13)

= 39

So, the total cost of 1 belt and 1 tie is $13 and $39 respectively.

5 0
3 years ago
triangle ABC above is isosceles with AB=AC and BC =48. the ratio of DE is 5:7. what is the length of DC
marshall27 [118]

Answer:

28

Step-by-step explanation:

Question Image is attached.

Triangle BED and Triangle CFD are similar.

We can let the length of BD be 5x and DC 7x

We also know BC = 48, thus we can write:

5x + 7x = 48

12x = 48

x = 4

Now, Since DC = 7x, we plug in x = 4 into it.

DC = 7x

DC = 7(4)

DC = 28

Length of DC is 28

6 0
3 years ago
Read 2 more answers
Find the value of x and y
mrs_skeptik [129]

Answer: y is 40 x is 60

Step-by-step explanation:

5 0
3 years ago
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If a,b, and c are prime numbers, do (a+b)(a+b) and cc have a common factor that is greater than 1?
Tanya [424]

Answer:

1. Information is not sufficient

2. Information is not sufficient

Step-by-step explanation:

Question Modified

If a,b, and c are prime numbers, do (a+b) and c have a common factor that is greater than 1?

(1) a,b, and c are all different prime numbers

(2) c≠2

Explanation

1. Let's assume values of 1,3 and 5 to a, b, and c respectively

a + b = 1+3 = 4

4 and 5 do not have any common factor aside 1

Let's assume values of 1,3 and 2 to a,b and c respectively

a + b = 1+3 = 4

4 and 2 have a common factor of 2

So, the available information is not sufficient

2.

Let's assume values of 2,7 and 3 to a b and c response

a + b = 2 + 7 = 9

9 and 3 have a common factor of 3

Also, let's assume values of 2,7 and 5 to a, b and c

a + b = 2 + 7 = 9

9 and 5 do not have a common factor

So, the available information is also not sufficient to answer the question.

3 0
3 years ago
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