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3 years ago

11

the small intestine is about 23 feet long while the large intestine is only 5 feet long what is the ratio of the large intestine

to small intestine write in 3 ways

1 answer:

ioda3 years ago

5 0

Answer:

it's answer is 4:1

Because length of small intestine is 6 m and length of large intestine is 1•5m

So 6/1•5 =4:1

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Ilya [14]

Answer:

B. cost(time)

Step-by-step explanation:

In the information given above, you can eliminate choices "A," and "D," since they're just using the cost of a repair and the time the mechanic works. This leaves us with either "B," or "C." The correct answer is "B," because the cost of the repair depends on whatever is inside the parenthesis (the time).

3 0

3 years ago

Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

2 years ago

See image for question.

kotegsom [21]

Answer:

<h3>#7</h3>

(a)

<u>Sample space:</u>

1*1, 1*2, 1*3, 1*4,
2*1, 2*2, 2*3, 2*4,
3*1, 3*2, 3*3, 3*4,
4*1, 4*2, 4*3, 4*4

Total 16 outcomes

(b)

(i) P(even) = 12/16 = 3/4
(ii) P(3x) = 7/16
(iii) P(perfect square) = 4/16 = 1/4

<h3>#8</h3>

(a) <u>Sample space:</u>

1T, 1H, 2T, 2H, 3T, 3H, 4T, 4H

Total 8 outcomes

(b)

(i) 1T, 3T

P(T and odd) = 2/8 = 1/4

(ii) 1H, 4H

P(H and square) = 2/8 = 1/4

(iii) 1H, 2H, 3H, 4H

P(H) = 4/8 = 1/2

6 0

3 years ago

Allyson accidentally missed her turn on her way to visit her aunt. By the time she realized her mistake, she had been driving fo

olya-2409 [2.1K]

Answer:

can u convert this to miles?

Step-by-step explanation:

6 0

3 years ago

1. You have three standard decks of cards in front of you. What is the probability of drawing a heart card from all three decks?

Paladinen [302]

Answer:

1.56%

Step-by-step explanation:

A standard deck of cards has 52 cards, and 13 of these are hearts, as there are 4 suits, and 52/4=13. This means the probability of choosing a heart card from a deck of cards is 1/4, or 25%. Now to find the probability of doing this from 3 decks in a row, we simply cube 1/4 to get 1/64, and in percentage this is ~1.56%.

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2 years ago