Question

Pls do it fast

Answer 1

Answer:

solution :

in the given figure AB=10.2cm, AC=14cm, AD=DC and AD perpendicular to BC.

now ,

in rt angle tirangle ADC,

angleACD=45 degree, angle DAC=45 degree now,

in triangle ABD,

angle BAD+angleABD+angleADB=180 DEGREE (sum of the sngle of triangle)

angle BAD+75+30=180

angle BAD=180-165      therefore,angle BAD=15

angle BAC =15+45=60

Area of triangle ABC=1/2×AB×AC×SIN 60

=1/2×10.2×14×√3/2

=61.83cm³ ans