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3 years ago

The sun of three conservative integers is -204. what is the largest integer?

Mathematics

1 answer:

Digiron [165]3 years ago

7 0

let us take the smallest integer as x

the second smallest as x+1

and the largest as x+2

since the sum is -204 we should add all of it to get the answer

therefore x+x+1+x+2=-204

3x+3=-204

3x=-204-3

3x=-207

x=-207/3

x=-69

the largest number is x+2

therefore the largest number is -67

to check whether it is right just add them and check whether we get - 204

therefore -69+-68+-67=

-204

therefore the answer is -67

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A = na . . . . . A = total area; n = number of costumes; 'a' = area per costume

46 2/3 = n(3 1/2)

n = (46 2/3)/(3 1/2) = (140/3)/(7/2) = (140/3)(2/7) = 40/3 = 13 1/3

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2 years ago

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The answer that you are looking for is
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3 years ago

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3 years ago

What is 5 1/2 x 2 1/3 ?

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3 0

3 years ago

A random sample of 250 students at a university finds that these students take a mean of 15.3 credit hours per quarter with a st

SpyIntel [72]

Answer: $15.3\pm0.198$

(15.102, 15.498)

Step-by-step explanation:

The formula to find the confidence interval $(\mu)$ is given by :-

$\overline{x}\pm z_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

, where n is the sample size

$s$ = sample standard deviation.

$\overline{x}$ = Sample mean

$z_{\alpha/2}$ = Two tailed z-value for significance level of $\alpha$ .

Given : Confidence level = 95% = 0.95

Significance level = $\alpha=1-0.95=0.05$

$s= 1.6$

$\overline{x}=15.3$

sample size : n= 250 , which is extremely large ( than n=30) .

So we assume sample standard deviation is the population standard deviation.

thus , $\sigma=1.6$

By standard normal distribution table ,

Two tailed z-value for Significance level of 0.05 :

$z_{\alpha/2}=z_{0.025}=1.96$

Then, the 95% confidence interval for the mean credit hours taken by a student each quarter :-

$15.3\pm (1.96)\dfrac{1.6}{\sqrt{250}}\\\\ =15.3\pm 0.19833\\\\=\approx15.3\pm0.198\\\\=(15.3-0.198,\ 15.3+0.198)=(15.102,\ 15.498)$

Hence, the mean credit hours taken by a student each quarter using a 95% confidence interval. =(15.102, 15.498)

5 0

3 years ago