Answer:
Jorge is using pencils at a rate of 6 packs a year or a rate of 2 packs every four months.
Step-by-step explanation:
1/3 of a year is four months so that would be 2 packs every four months and if you multiply that by three you’d get 12 month, or one year, and 6 packs of pencils.
Answer:
P (5 , 10)
Step-by-step explanation:
point A (1,4) and point D (7,13), AP/PD = 2:1
P (x,y) : x = x₁ + (a/(a+b) * (x₂-x₁)) y = y₁ + (a/(a+b) * (y₂-y₁)) .... a=2 b=1
x = 1 + 2/(2+1) * (7-1) = 5
y = 4 + 2/(2+1) * (13-4) = 10
P (5 , 10)
It would be 70=20x.
You would multiply 20 (snake’s speed) by x to get the cheetah’s maximum speed because the question says that the cheetah is 20 times faster than the snake
<h3><u>Answer:</u></h3>

<h3><u>Solution</u><u>:</u></h3>
we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

Here,
- hypotenuse = 23 feet
= 76°- Value of Sin
= 0.97 - Perpendicular = ?





ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>

Let "c" and "q" represent the numbers of bottles of Classic and Quantum that should be produced each day to maximize profit. The problem conditions give rise to 3 inequalities:
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.
Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.
To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.
Profit will be 6899p per day.
_____
The problem statement gives no clue as to the currency equivalent of 100p.