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kotegsom [21]
3 years ago
15

How many solutions does this equation have? -5(4 - x) = -5x + 20

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Answer

There is one solution

Step-by-step explanation:

-5(4 - x) = -5x + 20

-20 + 5x = -5x + 20

5x = -5x

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Since 10 is a positive the opposite must be negative. Opposite integer of 10 is -10 ( negative 10).

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I need to calculate a=8c-b divided by c, how do I calculate?
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Step-by-step explanation:

8xC-Bdivide by c


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What is the equation of the line that passes through the point (6,−4) and has a slope of -1/6
Luda [366]

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y + 4 = (-1/6)(x - 6)

Step-by-step explanation:

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The sum of three consecutive even numbers is 48. What is the biggest of these numbers?​
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Step-by-step explanation:

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3 0
3 years ago
Which of the following are solutions to the equation below?
scoundrel [369]

Answer:

The correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

Step-by-step explanation:

Given the expression

x^2+10x+25=8

Subtract 25 from both sides

x^2+10x+25-25=8-25

Simplify

x^2+10x=-17

Add 25 or 5² to both sides

x^2+10x+5^2=8

as

x^2+10x+5^2=\left(x+5\right)^2

so the expression becomes

\left(x+5\right)^2=8

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x+5=\sqrt{8}

Subtract 5 from both sides

x+5-5=2\sqrt{2}-5

x=2\sqrt{2}-5

solve

x+5=-\sqrt{8}

Subtract 5 from both sides

x+5-5=-2\sqrt{2}-5

x=-2\sqrt{2}-5

Therefore, the solution to the equation

x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5

Hence, the correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

6 0
3 years ago
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