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Digiron [165]
3 years ago
15

Idk can someone help

Mathematics
2 answers:
Alex3 years ago
7 0

Answer:

The answer is 20.

Step-by-step explanation:

Evgesh-ka [11]3 years ago
4 0

Answer:

if its 2/7 then 98 the luck also counts so 20

Step-by-step explanation:

luck+98+the premtier

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Two sets are equal if they contain the
kolbaska11 [484]

Answer:

Definition: Two sets are equal if they contain the

same elements. I.e., sets A and B are equal if

∀x[x ∈ A ↔ x ∈ B].

Notation: A = B.

Recall: Sets are unordered and we do not distinguish

between repeated elements. So:

{1, 1, 1} = {1}, and {a, b, c} = {b, a, c}.

Definition: A set A is a subset of set B, denoted

A ⊆ B, if every element x of A is also an element of B.

That is, A ⊆ B if ∀x(x ∈ A → x ∈ B).

Example: Z ⊆ R.

{1, 2} ⊆ {1, 2, 3, 4}

Notation: If set A is not a subset of B, we write A 6⊆ B.

Example: {1, 2} 6⊆ {1, 3}

3 0
3 years ago
Your friend wants to pay off his credit card with a balance of $880.00 and an interest rate of 16.65% APR by getting a loan from
djyliett [7]
U need to subtract 880.00 by 16.65 then add to that answer 5.35
4 0
4 years ago
Read 2 more answers
The equation of line m is 3x−5y=−4.
Alexandra [31]
It would be - \frac{5}{3}
8 0
4 years ago
.....................................
babunello [35]

\dfrac{q}{q^2+5q+6}+\dfrac{1}{q^2+3q+2}=\dfrac{q}{q^2+3q+2q+6}+\dfrac{1}{q^2+q+2q+2}\\\\=\dfrac{q}{q(q+3)+2(q+3)}+\dfrac{1}{q(q+1)+2(q+1)}\\\\=\dfrac{q}{(q+3)(q+2)}+\dfrac{1}{(q+1)(q+2)}\\\\=\dfrac{q(q+1)}{(q+1)(q+2)(q+3)}+\dfrac{1(q+3)}{(q+1)(q+2)(q+3)}\\\\=\dfrac{q^2+q+q+3}{(q+1)(q+2)(q+3)}=\dfrac{q^2+2q+3}{(q+1)(q+2)(q+3)}\to B.

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3 years ago
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ch4aika [34]
horizontal shift: 3 units to the left
vertical shift: 4 units down
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3 years ago
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