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3 years ago

Instructions: Find the Measure of the indicated angle to the nearest degree.

Mathematics

1 answer:

motikmotik3 years ago

7 0

Answer:

? = 35

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan ? = opp /adj

tan ? = 33/48

Take the inverse tan of each side

tan ^ -1 ( tan ? ) = tan ^ -1 ( 33/48)

? =34.50852299

? = 35

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Correct answers gets most brainiest!! :)

podryga [215]

Hello :)

Answer: x=11

Measure angel BAD= 122

Explanation:

To find X you have to make an equation

10x-49=5x+6

And then you solve for x

To find the angel measure of BAD, you have to add bac and cab to get bad

Bac= 10(11)-49 which equals 61

Cab= 5(11)+6=61

61+61= 122

Which is the measure of BAD

I hope this helps and have a wonderful rest of your night

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2 years ago

Daniel bought 2 boards of wood for a school project. one board is 24 inches long, and the other board is 20 inches long. he want

lisov135 [29]

Answer:

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2 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$