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4 years ago

What is the domain of the function f(x)=x−16? f(x)=x−16?

Mathematics

2 answers:

Damm [24]4 years ago

7 0

Answer:

Step-by-step explanation:

f(x)=x-16 is just a straight line with a slope of one at a y intercept of -16. Therefore, x can hit all numbers in the x axis making the domain x is in the element of all real numbers.

il63 [147K]4 years ago

4 0

Answer:

all real numbers

Step-by-step explanation:

literally the domain can be anything but the range is limited because of the vertical line check

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Find what w equals 4(3w+5)−2w=70

Luba_88 [7]

4(3w+5)-2w=70
10w+20=70
10w+20-20=70-20
10w=50
10w/10=50/10
w=5

8 0

3 years ago

Read 2 more answers

It says to find the area of the figure but I have no idea what to do

Westkost [7]

2.5 is also on the top and try multiplying 2.5 and 10

6 0

3 years ago

Help please :)) 10 points

DaniilM [7]

Answer:

54 -3n²

Step-by-step explanation:

The square of a number (n) is represented by n². Three times that value is represented by 3n².

The relation "a is subtracted from b" is represented as ...

b - a

When 3n² is subtracted from 54, the appropriate representation is ...

54 -3n²

6 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

4 years ago

A boat travels 30 miles up the river in the same amount of time it takes to travel 38 miles down the same river. If the current

Ksenya-84 [330]

X miles per hour - speed of the boat in still water
(x - 2) - speed up the river
(x + 2) - speed down the river

$\frac{30}{x - 2}$ = $\frac{38}{x + 2}$
30 * (x + 2) = 38 * (x - 2)
30x + 60 = 38x - 76
- 8x = - 136
x = 17 miles per hour - the speed of the boat in still water.

5 0

3 years ago