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Helga [31]
3 years ago
8

Divide 3.5 × 108 by 6.6 × 104 and write the answer in scientific notation.

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
5 0
3.5×10⁸ / 6.6×10⁴ = <span>5303.03--</span>
<span>
In scientific notation it is 5.3 </span>×10³. You move the decimal point until you have exactly one digit on the left of it.

Answer a is the correct one.
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30 treadmills to 36 elliptical machines ratio simplest form
Ivanshal [37]

Answer:

5 to 6 or 5:6 or 5/6

Step-by-step explanation:

30/36 = 15/18 = 5/6

8 0
3 years ago
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Which term is correct when simplifying √128?<br><br> A.) 16<br> B.) 12<br> C.) 10<br> D.) 8√2
alina1380 [7]
When dealing with roots, we want to factor to see if it's possible

128  = 2 \times 64
= 2 \times 2 \times 32
= 2 \times 2 \times 2 \times 16
= 2 \times 2 \times 2 \times 2 \times 8
= 2 \times 2 \times 2 \times 2 \times 2 \times 4
= 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2

now since we're dealing with square roots, we circle every pair of numbers we see in the final factoring
so..
= (2 \times 2) \times (2 \times 2) \times (2 \times 2) \times 2

now for every circled pair, we take only 1 of the 2 circled and bring it outside
anything left uncircled stays inside the root
so..
= 2 \times 2 \times 2 \times \sqrt{2}

now simply multiply
8 \sqrt{2}
3 0
3 years ago
A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
3 years ago
24 divided by 4 times d
nadya68 [22]

Answer:

i think 6 not sure tho sorry if its worng

3 0
3 years ago
ASAP!!!!! Help please ‼️
ZanzabumX [31]

Answer: The answer should be 3.

Step-by-step explanation: You plug in 2 instead of X and that’s it. Then you calculate your equation, and receive your answer.

4 0
3 years ago
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