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Law Incorporation [45]
2 years ago
5

Find the distance between the two points.(-7,4/19) and (7,4/9)

Mathematics
1 answer:
Dafna1 [17]2 years ago
7 0

Answer:

<h2>d=(14,0)</h2>

Step-by-step explanation:

<h2>√(7-(-7))^+(4/19-4/19)^</h2><h2>√(7+7)^+(0)^</h2><h2>√(14)^+0</h2><h2>= 14</h2>
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Solve the following questions and check your results 3) t = 3/4 (+-2)​
balu736 [363]
The answer would be: t= -5/4
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3 years ago
Is a square a rectangle and a rhombus? explain (pls answer asap)
Nesterboy [21]

Answer:

No

Step-by-step explanation:

A square is a square. I don't even know how this is a question-

4 0
2 years ago
the polygons in each pair are similar. find the scale factor of the smaller figure to larger figure.​
katovenus [111]

Answer:

Scale factor = \frac{1}{2}

Step-by-step explanation:

From the picture given in the question,

If the larger figure is dilated to form the smaller figure,

Scale factor by which a figure is dilated with is determined by the expression,

Scale factor = \frac{\text{Measure of one side of the smaller figure}}{\text{Measure of the corresponding side of the larger figure}}

                    = \frac{3}{6}

                    = \frac{1}{2}

8 0
2 years ago
25. The triangle below can be subject to reflection, ,
slega [8]

Answer:

B

Step-by-step explanation:

B is the only answer that has the same numbers as the figure included. Triangle side size does not change in a reflection, rotation, or translation.

Hope this helps! :)

6 0
3 years ago
Read 2 more answers
A fence for a rectangular garden with one side against an existing wall is constructed by using 60 feet of fencing. What is the
Y_Kistochka [10]

Step-by-step explanation:

A fence for a rectangular garden with one side against an existing wall is constructed by using 60 feet of fencing.

Perimeter of rectangle (3 sides)= 60 feet

Let 'x' be the width of the wall

Perimeter = 2(length)+2(width)\\60=2(length)+2x\\\\60-2x=2(length)\\\frac{60-2x}{2} =length\\Length =30-x

Formula for the area of the rectangle is

Area=length \cdot width\\A=length(x)

Replace the length we got using perimeter

A=(30-x)(x)\\A(x)= 30x-x^2

To find out the maximum are we take derivative

A'(x)= 30-2x\\0=30-2x\\-30=-2x\\x=15

find out second derivative to check whether x=15 is maximum

A''(x)=-2

second derivative is negative

So, Maximum area at x=15

To find maximum area we plug in 15 for x in A(x)

A(x)=30x-x^2\\A(15)=30(15)-15^2\\A(15)=225

So, maximum area is 225 square feet

3 0
3 years ago
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