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2 years ago

743 times 295 answer please

Mathematics

2 answers:

Mamont248 [21]2 years ago

5 0

The answer is 219,775

IrinaVladis [17]2 years ago

4 0

3 2
2 1
743
x 295
______
3715
66870
+148600
________
219,185

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Extra points and top BRAINIEST!!!<br> An is parallel to DE in the map below

Margaret [11]

Answer:

Third option

Step-by-step explanation:

$\frac{9}{6} = \frac{15}{x} \\$

is the correct answer.

6 0

3 years ago

Read 2 more answers

each Saturday morning Janie works 5 hours and earns $35.75. How much does Janie earn for each hour she works?

bulgar [2K]

Answer:

$7.15

Step-by-step explanation:

You would get this by dividing $35.75 by 5.

8 0

2 years ago

Round 78.8 to the tenths

Nadusha1986 [10]

78.8 rounded to the nearest tenths is 78.8

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2 years ago

The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation

Nutka1998 [239]

Answer:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.917,0.303)$

Where $\mu=0.917$ and $\sigma=0.303$

We have the following info from a sample of n =37:

$\bar X= 0.872$ the sample mean

And we want to find the following probability:

$P(\bar X \leq 0.872)$

And we can use the z score formula given by;

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for the value of 0.872 we got:

$z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903$

And we can find this probability to find the answer:

$P(z$

And using the normal standar table or excel we got:

$P(z$

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3 years ago

14 = 6x4+b <br><br> I WILL MARK BRAINLYIEST FOR 1ST PERSON

Ira Lisetskai [31]

14 = 6x4 + b
14 = 24 + b
-10 = b

Hope this is accurate & helpful! Let me know if there are any errors or if you have any additional questions.

7 0

1 year ago