Juanita score was 5 over par on the first 9 holes. her score was 4 under par on the second 9 holes

George has $23 to spend on art supplies. He wants to buy markers, paper, and glue. If the total cost of the markers and paper is

Reil [10]

Answer:

14>9=p

Step-by-step explanation:

6 0

3 years ago

I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ

Dmitrij [34]

Answer:

$V = \frac{450L - 6 L^{3} }{10}$

Step-by-step explanation:

The volume of a cuboid can be determined simply by the formula: V= LWH

(where: L is length, H is height and W is width).

In this particular case the base is a square, which means the length and width are equal. Hence we can modify the equation of volume:

$V = L^{2} H$

Now we need to find the value of H in terms of L. For this we can develop the equation for cost incurred in building the storage shed. We find the area of each side of the cuboid, and then we multiply it by cost per square feet to find the total cost incurred; as shown below:

Area:

Base: $L$ × $L = L^{2}$

Roof: $L$ × $L = L^{2}$

Side: $4 H$ × $L = 4HL$ (we have considered all four sides)

Cost:

Base: 4 $L^{2}$

Roof: 2 $L^{2}$

Side: $2.50 * 4HL = 10 HL$

Total cost:

4 $L^{2}$ + 2 $L^{2}$ + 10 $HL$ = 450

We simplify this equation further:

6 $L^2$ + 10HL = 450

10HL = 450 - 6 $L^2$

$H = \frac{450- 6 L^2}{10L}$

We now have the value of H, which we can substitute in the formula of Volume we deduced earlier:

substituting $H = \frac{450-6L}{10L}$ in $V = L^{2} H$ :

$V = L^2$ × $\frac{450 - 6L }{10L}$

Simplifying it further:

$V = L$ × $\frac{450 - 6L}{10}$

$V= \frac{450L - 6L^3}{10}$ is the final answer.

3 0

3 years ago

There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3

jekas [21]

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

7 0

3 years ago

I need the result of 14?2?7?3?9=10

PilotLPTM [1.2K]

Answer: yes

Step-by-step explanation:

7 0

2 years ago

pleeeeeeeeeeeease hellllllllp meeeeeee the circle has a center of 0.its raduis is 3 cm,and the central angle A measures 100.what

Vsevolod [243]

Answer:

2.5 pi

Step-by-step explanation:

Comment

If you were trying to get the area of a whole circle, you would use

Area = pi r^2

You have to modify the formula to show that just part of the circle has an area that you are interested in.

The new formula is

Area = (theta/360) pi r^2

Givens

r = 30 cm

theta = 100

Solution

Area = (100 / 360) * pi * r^2 Substitute the givens into this formula

Area = (5 / 18) * pi * 3^2 Expand

Area = (5 / 18) * pi * 9 Cancel 9 into 18

Area = 5/2 * pi

Area = 2.5 * pi

7 0

2 years ago