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SVETLANKA909090 [29]
3 years ago
11

Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.

Mathematics
1 answer:
Virty [35]3 years ago
7 0

Answer:

(A)128^{x/3}

(D)(4(2^{1/3}))^x

Step-by-step explanation:

We want to determine which of the expression is equivalent to:

\sqrt[3]{128}^ x

By the law of indices:

\sqrt[3]{128}=128^{1/3}\\$Therefore:\\\sqrt[3]{128}^ x \\=(128^{1/3})^x\\=128^{x/3}

Similarly:

\sqrt[3]{128}^ x \\=\sqrt[3]{64*2}^ x\\=(4\sqrt[3]{2})^ x\\=(4(2^{1/3}))^x

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Triangle: solve for x
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Answer:

6 root two

Step-by-step explanation:

geometric mean for leg t.

24*3=x2

x2=72

x=root(72)

6 root two

if my answer helps please mark as brainliest.

6 0
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Answer to the question
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What is m months

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Use the quadratic formula to solve for the roots of the following equation.<br> x 2 – 4x + 13 = 0
Artyom0805 [142]
  • Quadratic Formula: x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} , with a = x^2 coefficient, b = x coefficient, and c = constant

With our equation, plug in the values:

x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}

Next, solve the exponent and multiplications:

x=\frac{4\pm \sqrt{16-52}}{2}

Next, solve the subtraction:

x=\frac{4\pm \sqrt{-36}}{2}

Next, factor out i (i = √-1):

x=\frac{4\pm \sqrt{36}i}{2}

Next, solve the square root:

x=\frac{4\pm 6i}{2}

Lastly, divide and <u>your answer is:</u>

x=2\pm 3i

5 0
3 years ago
Read 2 more answers
The mean time required to repair breakdowns of a certain copying machine is 93 minutes. The company which manufactures the machi
Sonja [21]

Answer:

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

p_v =P(t_{(72)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=88.8 represent the sample mean

s=26.6 represent the sample standard deviation for the sample  

n=73 sample size  

\mu_o =93 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 93 min, the system of hypothesis would be:  

Null hypothesis:\mu \geq 93  

Alternative hypothesis:\mu < 93  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=73-1=72  

Since is a one side test the p value would be:  

p_v =P(t_{(72)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

5 0
3 years ago
How much force did the car apply to the golf cart?
lubasha [3.4K]

Answer: 1500

Step-by-step explanation:

5 m/s in 0 m/s in 1 sec

so its 1500

4 0
3 years ago
Read 2 more answers
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