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Alex73 [517]
3 years ago
9

How do you identify a pair of isotopes? Also, what are isotopes?

Chemistry
1 answer:
saveliy_v [14]3 years ago
8 0

Isotopes are elements with same atomic number but different mass number. Hydrogen and Deuterium are isotopes with same atomic number but different mass number. Hydrogen have atomic number 1 and mass number 1 where as deuterium have atomic number 1 but mass number 2

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Sonni added 23.79 mL of KOH to 20.00 mL of 0.393 M HF until the equivalence point was reached. What is the concentration of conj
madreJ [45]

Answer:

0.1795 M

Explanation:

From the given information:

The equation is:

\mathbf{HF_{(aq)}+ KOH_{(aq)} \to KF _{(aq)} + H_2O}

From the above equation, the reaction will go to completion due to the strong base:

At the equivalence point, moles of acid (HF) will be equal to moles of base (KOH)

\text{Number of moles = Volume}  \times Molarity

Thus. since moles of HF = moles of KOH

Then; 0.020 × 0.393 M = 0.02379 × (x) M

(x) M = \dfrac{0.02 \times 0.393 \ M}{0.02379}

(x) = 0.3304 M

Thus, the molarity of KOH = 0.3304 M

Using the balanced neutralization reaction;

moles of HF = moles of KOH = moles of conjugate base = 0.00786 mol

∴

Volume = 0.020 L + 0.02379 L

Volume = 0.04379 L

Volume of the solution =  0.04379 L

Therefore; Molarity = \dfrac{moles}{volume}

Molarity = \dfrac{0.00786  \ mol}{0.04379  \ L}

Molarity = 0.17949 mol/L

= 0.1795 M

7 0
3 years ago
What is the answer to the formula 12+6/2+10?<br> 0 25<br> O 14<br> O 19<br> 03.6
aleksandrvk [35]

The answer was 25

Do according to bodmas rule

6 0
3 years ago
Li2SO4 _____ an electrolyte in solution.<br> A. Is <br> B. Is not
Rasek [7]

Answer:

a

Explanation:

it is an electrolyte because of its strong polar chemical bond

8 0
3 years ago
Read 2 more answers
How many grams is .15mol of argon
bonufazy [111]

Answer:

The answer is 39.948.

Explanation:

8 0
3 years ago
A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
Andre45 [30]

Answer:

* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

* m=2.46m

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

7 0
3 years ago
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